正则表达式:为 r:a.?b.?c 创建异常 [英] regex: creating an exception for r:a.?b.?c

问题描述

我需要创建一个正则表达式来过滤任何字母之间有 0 到 1 个随机字符的厨房"的任何变体，但它需要为厨房"做一个例外

I need to create a regex expression that will filter any variant of "kitchen" that has between 0 and 1 random characters between any of the letters, but it needs to make an exception for "kitchen"

我已经有了以下东西，但我需要它不要赶上厨房"

I already have the following, but I need to it not catch "kitchen"

r:k.?i.?t.?c.?h.?e.?n

我不介意做多个表达式，但显然对于 r:k.?itchen、r:ki.?tchen 等的每个变体都有一个表达式是不可行的.

I don't mind doing multiple expressions, but obviously it isn't viable to have an expression for every variant of r:k.?itchen, r:ki.?tchen etc.

有人可以帮忙吗?谢谢.

Can anyone help? Thanks.

推荐答案

您可以先行确认字符串不完全是厨房"

You can do a lookahead to make sure the string is not exactly 'kitchen'

r:(?!kitchen)k.?i.?t.?c.?h.?e.?n

演示

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