正则表达式 - 以特定字符串开头但不以另一个子字符串结尾 [英] Regex - starts with a particular string but does not end with another substring

问题描述

给定两个字符串 s1 和 s2，我正在尝试编写一个正则表达式来匹配以 s1 开头但不匹配的字符串以 s2

Given two strings s1 and s2, I am trying to write a regex that will match a string that starts with s1 but does not end with s2

示例(s1=TEST，s2=BAD)

Example (s1=TEST, s2=BAD)

• TEST-101 匹配
• TEST-SOME-DESC 匹配
• TEST-101-BAD 不应匹配
• TEST-SOME-DESC-BAD 不应匹配

这是我在这个例子中尝试过的，但它不起作用:/^TEST-.*((?!BAD))$/

Here is what I tried for this example but it does not work: /^TEST-.*((?!BAD))$/

推荐答案

试试这个:

/^(?!.+BAD$)TEST-.*/

这匹配开始，继续并拒绝以错误字符串结尾的任何内容，然后匹配所需的模式.

This matches the start, goes ahead and rejects anything ending in the bad string, then matches the desired pattern.

这是通过所有四个测试的演示(点击运行测试"" 在底部验证).

Here's a demo that passes all four of your tests (click "RUN TESTS" at the bottom to verify).

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