正则表达式匹配科学记数法 [英] Regex to match scientific notation

问题描述

我正在尝试以科学记数法匹配数字(来自此处的正则表达式):

I'm trying to match numbers in scientific notation (regex from here):

scinot = re.compile('[+\-]?(?:0|[1-9]\d*)(?:\.\d*)?(?:[eE][+\-]?\d+)')
re.findall(scinot, 'x = 1e4')
['1e4']
re.findall(scinot, 'x = c1e4')
['1e4']

我希望它匹配 x = 1e4 但不匹配 x = c1e4.我应该改变什么?

I'd like it to match x = 1e4 but not x = c1e4. What should I change?

更新:此处的答案相同问题:它错误地匹配 'x = c1e4'.

Update: The answer here has the same problem: it incorrectly matches 'x = c1e4'.

推荐答案

在正则表达式末尾添加锚点并在数字前添加替代空格或等号:

Add anchor at the end of regex and alternative space or equal sign before the number:

[\s=]+([+-]?(?:0|[1-9]\d*)(?:\.\d*)?(?:[eE][+\-]?\d+))$

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