正则表达式匹配连续的 n(字母数字) [英] Regex to match consecutive n (alpha numeric)

问题描述

我正在尝试匹配字符串中连续的 n 个(字母数字)字符.

I am trying to match consecutive n(alpha numeric) characters in a string.

其中 n = 3

i7g172w2n             YES (it has 3 consecutive number)

adab172cd             NO (it has 4 consecutive alpha even though it has 3 consecutive number)

aaa172afa             YES (it has 3 consecutive number and 3 consecutive alpha)

ab21cd172             YES

abc21a3d3             YES

有人能帮我吗.

这是我的正则表达式:(\D(\d{3})\D)|\d([a-z]{3})\d 不起作用.

Here is my regex : (\D(\d{3})\D)|\d([a-z]{3})\d not working.

推荐答案

尝试使用以下正则表达式.

Try with following regex.

正则表达式: ^(?:(?:\d{0,3}[az]{1,3}\d{1,3})+|(?:[az]{0,3}\d{1,3}[az]{1,3})+)$

说明:基本上我所做的是匹配以下模式.

Explanation: Basically what I have done is matched following patterns.

1. (?:\d{0,3}[a-z]{1,3}\d{1,3})+

• ( 0-3 Digit 1-3 Alphabets 1-3 Digits ) <- 超过一次.

• ( 0-3 Digit 1-3 Alphabets 1-3 Digits ) <- More than one time.

(?:[a-z]{0,3}\d{1,3}[a-z]{1,3})+

• ( 0-3 Alphabets 1-3 Digits 1-3 Alphabets ) <- 超过一次.

• ( 0-3 Alphabets 1-3 Digits 1-3 Alphabets ) <- More than one time.

因为两者是交替的，因此这两个模式中的任何一个都会匹配.

Since both are in alternation, hence either of these pattern will be matched.

对于字符串 i7g172w2n 子匹配将是 i-7-g-172-w-2-n.符合规范.

For string i7g172w2n sub matches will be i-7-g-172-w-2-n. Which fits into the specifications.

对于字符串 adsb172cd 子匹配将是 adsb-172-cd.由于 adsb 超过长度 3.因此不会匹配.

For string adsb172cd sub matches will be adsb-172-cd. Since adsb exceeds length 3. Hence won't be matched.

与abc2p7373类似，7373超过长度3.

Regex101 演示

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