PHP正则表达式检查英文名称 [英] PHP regex to check a English name

问题描述

寻找一个正则表达式来检查一个有效的英文名称，即:

Looking for a regex to check a valid English name, i.e.:

• 仅 A-Z、a-z、空格
• 名字，(可选)中间名，姓氏

一个可接受的例子:John von Neumann

谢谢！

编辑(添加检查代码):

EDIT (added checking code):

#!/usr/bin/php

<?php

    function check_name($regex, $name)
    {
        $rc = 'Bad';
        if (preg_match($regex, $name)) {    
            $rc = 'Good';
        }
        return '|' . $name . '| ' . $rc . "\n";
    }

    $regex = '/(?:[A-Za-z]+(?:\s+|$)){2,3}/';
    echo check_name($regex, 'First');
    echo check_name($regex, 'First Last');
    echo check_name($regex, 'Two  Spaces');
    echo check_name($regex, 'First Middle Last');
    echo check_name($regex, 'First Middle Last Fourth');
    echo check_name($regex, 'First 123');

?>

推荐答案

如果您所陈述的规则确实是您想要的，那么以下方法可行:

If the rules you've stated are actually what you want, the following would work:

/^(?:[A-Za-z]+(?:\s+|$)){2,3}$/

但是，现实生活中有不少名字不符合这些规则，例如O'Malley"、Jo-Jo"等.

However, there are quite a few real-life names that don't fit in these rules, like "O'Malley", "Jo-Jo", etc.

你当然可以很容易地扩展这个正则表达式以允许其他字符 - 只需将它们添加到括号中即可.例如，要允许撇号和破折号，您可以使用 [A-Za-z'-] (- 必须在末尾，否则将被解释作为一个范围).

You can of course extend this regex fairly easily to allow other characters - just add them into the brackets. For instance, to allow apostrophes and dashes, you could use [A-Za-z'-] (the - has to be at the end, or it will be interpreted as a range).

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