从字符串数组替换字符串的所有出现 [英] Replace all occurences of a string from a string array

问题描述

我有一个字符串数组，如：

 的String []项目= {一，二，三，一，二，一};
 

我想一次更换零所有的人。
那么项目应该是：

{零，二，三，零，二，零};

我找到了一个解决方案我如何更换在一个字符串数组项？。

但是，这只能更换一次出现。这是最好的方法/步骤来代替所有出现？

任何帮助AP preciated。

解决方案

 的String []项目= {一，二，三，一，二，一};
项目= items.Select（！？s =＆GT; S =一S：零）ToArray的（）。
 

从这里

找到答案 ..

感谢所有

I have a string array like:

 string [] items = {"one","two","three","one","two","one"};

I would like to replace all ones with zero at once. Then items should be:

{"zero","two","three","zero","two","zero"};

I found one solution How do I replace an item in a string array?.

But it will replace the first occurrence only. Which is the best method/approach to replace all occurrences?

Any help appreciated.

解决方案

string [] items = {"one","two","three","one","two","one"};
items =  items.Select(s => s!= "one" ? s : "zero").ToArray();

Found answer from here..

Thanks all

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