如何根据数字/非数字拆分字符串(使用正则表达式?) [英] How to split a string (using regex?) depending on digit/ not digit

问题描述

我想在python中将一个字符串拆分为一个列表，具体取决于数字/不是数字.例如，

5 55+6+ 5/

应该返回

['5','55','+','6','+','5','/']

我现在有一些代码循环遍历字符串中的字符并使用 re.match("\d") 或 ("\D") 测试它们.我想知道是否有更好的方法来做到这一点.

P.S:必须兼容python 2.4

解决方案

假设 6 和 5 之间的 + 需要匹配(你错过了)，

<预><代码>>>>进口重新>>>s = '5 55+6+ 5/'>>>re.findall(r'\d+|[^\d\s]+', s)['5', '55', '+', '6', '+', '5', '/']

I want to split a string into a list in python, depending on digit/ not digit. For example,

5 55+6+  5/

should return

['5','55','+','6','+','5','/']

I have some code at the moment which loops through the characters in a string and tests them using re.match("\d") or ("\D"). I was wondering if there was a better way of doing this.

P.S: must be compatible with python 2.4

解决方案

Assuming the + between 6 and 5 needs to be matched (which you're missing),

>>> import re
>>> s = '5 55+6+ 5/'
>>> re.findall(r'\d+|[^\d\s]+', s)
['5', '55', '+', '6', '+', '5', '/']

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