在字符串列表中查找字符串列表，返回布尔值 [英] find list of strings in list of strings, return boolean

问题描述

我正在尝试使用 python 中的字符串列表，但不知何故我找不到好的解决方案.我想在字符串列表中查找字符串列表并返回布尔值:

I am trying to work with lists of strings in python and somehow I can't find a good solution. I want to find a list of strings within a list of strings and return boolean values:

import re
sentences = ['Hello, how are you?',
             'I am fine, how are you?',
             'I am fine too, thanks']
bits = ['hello', 'thanks']

re.findall(sentences, bits)

# desired output: [True, False, True]

因此，如果句子字符串包含一个或多个位，我想获得一组带有 True 的布尔值.我也试过

So I want to get an array of booleans with True, if the sentences string contains one or more of the bits. I also tried

bits = r'hello|thanks'

但我总是收到错误'unhashable type:'list''.我尝试将列表转换为数组，但错误只是显示不可哈希类型:‘列表’".如有任何帮助，我将不胜感激！

but I always get the error 'unhashable type: 'list''. I tried converting the lists to arrays, but then the error just says 'unhashable type: 'list''. I would be grateful for any help!

推荐答案

一种选择是使用嵌套列表推导式:

One option is to use a nested list comprehension:

sentences = ['Hello, how are you?',
             'I am fine, how are you?',
             'I am fine too, thanks']
bits = ['hello', 'thanks']

[any(b in s.lower() for b in bits) for s in sentences]
# returns:
[True, False, True]

如果你想使用正则表达式，你需要将bits与一个管道符连接起来，但你仍然需要单独检查sentences中的每个句子.

If you want to use a regular expression, you need to join bits with a pipe character, but you will still need to check each sentence in sentences individually.

[bool(re.search('|'.join(bits), s, re.IGNORECASE)) for s in sentences]
# returns:
[True, False, True]

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