正则表达式 - 排除域 [英] Regex - exclude domain

问题描述

假设，我有域名

@abc.com.

如果有 3 个或更多外部收件人，我需要匹配模式.

例如:致:

<块引用>

[e-mail];[e-mail]；[e-mail];[e-mail];[e-mail];[e-mail];[e-mail];[e-mail]

我已经拥有的正则表达式如下所示:

到:(.*@[^a][^b][^c][^.][^c][^o][^m].*){3,}

它有点工作，但看起来很讨厌.也许以某种方式实现这个?^((?!@abc.com).){3,}

谢谢！对我很有帮助

解决方案

您需要匹配:

1. A "@"
2. 后面没有"abc."
3. 直到下一个"@"
的更多字符
4. (1)、(2) 和 (3) 重复 3 次

此表达式将匹配具有 3 个外部收件人的主题:

(?:@(?!abc[.]).*?){3}

(?!abc[.]) 以检查您的域后面没有跟随它..*? 用于在不同的 @ s 之间使用字符.

您也可以将 abc[.] 更改为 abc[.]com(?:[; ]|$) 或您的真实域名.

Lets say, I have domain

@abc.com.

I need to match the pattern if there are 3 or more external recipients.

For example: To:

[e-mail]; [e-mail]; [e-mail]; [e-mail]; [e-mail]; [e-mail]; [e-mail]; [e-mail]

The regex I already have looks like that:

To:(.*@[^a][^b][^c][^.][^c][^o][^m].*){3,}

Its kinda working, but looking nasty. Maybe somehow implement this? ^((?!@abc.com).){3,}

Thank you! It would help me a lot

解决方案

You need to match:

1. A "@"
2. not followed by "abc."
3. more characters until the next "@"
4. (1), (2) and (3) repeated 3 times

This expression will match a subject with 3 external recipients:

(?:@(?!abc[.]).*?){3}

DEMO

---

It uses the negative lookahead (?!abc[.]) to check it's not followed by your domain. The .*? is there to comsume the chars between different @s.

You may as well change abc[.] to abc[.]com(?:[; ]|$) or your real domain.

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