如何从html图像标签中获取class和src [英] How to get class and src from html image tag

问题描述

我想使用正则表达式检索图像标签的类和 src.class 和 src 的位置可以任意.

I want to retrieve the class and src of image tag using regex. The position of class and src can be anywhere.

我可以从 /<img[^>]* src="([^\"]+)"[^>]*> 得到 src/i

I am able to get src from /<img[^>]* src="([^\"]+)"[^>]*>/i

<img width="100" height="100" src="/woocom.png" class="hello hel" alt="woo">

<img width="100" height="100" class="hello hel" src="/woocom.png"  alt="woo">`

在此处尝试在线正则表达式

推荐答案

因为有 PHP 标签.我不建议在这种情况下使用正则表达式.正则表达式是一把锤子，当你理解它时，你周围的一切看起来都像钉子.在 PHP 中，我们有用于此任务的 DOMDocument 类.例如下面:

Since there is a PHP tag. I won't recommend using Regular Expressions for this situation. Regular Expression is a hammer and when you understand it, everything around you looks like nail. In PHP we have DOMDocument class for this task. Eg below:

$d = new DOMDocument();
$d->loadHTML('<img width="100" height="100" src="/woocom.png" class="hello hel" alt="woo">');
$images = $d->getElementsByTagName('img');
foreach ($images as $image) {
  echo $image->getAttribute('src');
  echo $image->getAttribute('class');
}

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