如何在 Javascript 中使用正则表达式来提取 URL 路径的特定部分 [英] How do I use a regex in Javascript to extract specific parts of a URL path

问题描述

现在，我正在尝试采用这种格式的网址:

Right now, I'm trying to take a URL in this format:

https://www.example.com/{section}/posts/{number}

并获取部分和编号.我需要用正则表达式来做；我不能只是把它分成一个部分数组.我试过了:

and get section and number. I need to do it with a regex; I cannot just break it into a parts array. I have tried:

var sect = myURL.match('https://www.example.com/[^/]+');

但我得到作为输出 "https://www.example.com/{section}" 我希望能够获得 section 和编号.我如何在 Javascript 中执行此操作?

but I get as output "https://www.example.com/{section}" I want to be able to get the section and the number. How do I do this in Javascript?

推荐答案

您可以将 matches 的输出分配给多个变量，如下所示:

You can assign output of matches to multiple variables like this:

var myURL = 'https://www.example.com/mysection/posts/1234';

[$0, sec, num] = myURL.match(/^https?:\/\/www\.example\.com\/([^\/]+)\/posts\/(\d+)\/?$/);

console.log(sec)
//=> mysection

console.log(num)
//=> 1234

正则表达式详情:

• ^:开始
• https?:\/\/www\.example\.com\/:
• ([^\/]+):匹配任何不是 / 的字符的 1+ 并捕获为组 #1
• \/posts\/:匹配/posts/
• (\d+):匹配 1+ 位数字并捕获为第 2 组
• \/?$:在结束前匹配一个可选的尾随/

• ^: Start
• https?:\/\/www\.example\.com\/:
• ([^\/]+): Match 1+ of any character that is not / and capture as group #1
• \/posts\/: Match /posts/
• (\d+): Match 1+ digits and capture as group #2
• \/?$: Match an optional trailing / before end

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