如何对第 9 个反向引用后的正则表达式进行分组? [英] How do I group regular expressions past the 9th backreference?

问题描述

好的，所以我试图将记事本++中的第 9 个反向引用分组.维基说我可以使用组命名来超过第 9 个参考.但是，我似乎无法正确使用语法来进行匹配.为了简单起见，我只从两组开始.

Ok so I am trying to group past the 9th backreference in notepad++. The wiki says that I can use group naming to go past the 9th reference. However, I can't seem to get the syntax right to do the match. I am starting off with just two groups to make it simple.

示例数据

1000,1000

正则表达式.

(?'a'[0-9]*),([0-9]*)

根据 文档，我需要执行以下操作.

According to the docs I need to do the following.

(?<some name>...), (?'some name'...),(?(some name)...)
Names this group some name.

然而，结果却是找不到我的文字.有什么建议吗?

However, the result is that it can't find my text. Any suggestions?

推荐答案

你可以像那些 < 一样简单地引用组 > 910

You can simply reference groups > 9 in the same way as those < 10

即 10 美元是第十组.

i.e $10 is the tenth group.

对于(天真的)例子:

字符串:

For (naive) example:

String:

abcdefghijklmnopqrstuvwxyz

abcdefghijklmnopqrstuvwxyz

正则表达式查找:

Regex find:

(?:a)(b)(c)(d)(e)(f)(g)(h)(i)(j)(k)(l)(m)(n)(o)(p)

(?:a)(b)(c)(d)(e)(f)(g)(h)(i)(j)(k)(l)(m)(n)(o)(p)

替换:

10 美元

结果:

kqrstuvwxyz

kqrstuvwxyz

我的测试是在 Notepad++ v6.1.2 中进行的，并给出了我预期的结果.

My test was performed in Notepad++ v6.1.2 and gave the result I expected.

更新:这仍然适用于 v7.5.6

Update: This still works as of v7.5.6

SarcasticSully 复活了这个来问这个问题:

SarcasticSully resurrected this to ask the question:

如果要替换为第 1 组后跟字符 '0' 怎么办?"

"What if you want to replace with the 1st group followed by the character '0'?"

为此将替换更改为:

$1\x30

用组 1 和十六进制字符 30 替换 - 这是 ascii 中的 0.

Which is replacing with group 1 and the hex character 30 - which is a 0 in ascii.

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