如何简单数组转换成二维阵列（矩阵）中的Fortran？ [英] How to convert simple array into two-dimensional array(matrix) in Fortran?

问题描述

我不得不从文件中读取数据和所有数据存储在一个一维阵列。
然而，一些数据我有一个矩阵（2维数组）来存储我怎样才能做到这一点？

I had to read data from a file and store all data in a one dimensional array. However, Some data I have to store in a matrix (2 dimensional array) How Can I do this?

例如，如果我的数据是 1X7 阵列 [1,2,3,1,5,2,8] 和第一至第六属于矩阵 2×3 我怎么能存储在一个新的数组变量？

For example if my data is 1x7 array [1,2,3,1,5,2,8] and the first to 6th belong to a matrix 2x3 how can I store in a new array variable?

推荐答案

假设你的7个元素的数组被称为 array7 ，那么下面前pression应返回一个包含 array7

Suppose that your 7-element array is called array7, then the following expression should return a 2x3 array containing the first 6 elements of array7

reshape(array7(1:6),[2,3])

如果说放元素融入到新的数组中的顺序错误，请尝试

If that puts the elements into the new array in the wrong order, try

reshape(array7(1:6),[2,3],order=[2,1])

请注意，我已经在第二版中使用了一个名为可选参数，还有一个可选的参数（垫），这将是，默认情况下，第三个参数重塑。

Note that I've used a named optional argument in the second version, there is another optional argument (pad) which would be, by default, the 3rd argument to reshape.

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