如何从Java中的标准输入读取整数数组？ [英] How to read array of integers from the standard input in Java?

问题描述

在从标准输入一行我有3种类型的整数：第一个整数ID，第二个整数N - 一些号码，后跟随N个整数，用一个空格separeted我想存储在数组或ArrayList中。我怎样才能做到这一点使用的BufferedReader？我有以下的code：

  BR的BufferedReader =新的BufferedReader（新的InputStreamReader（System.in））;
。字符串[]行= br.readLine（）分裂（）;
INT ID =的Integer.parseInt（行[0]）;
INT N =的Integer.parseInt（行[1]）;
 

我的问题是是否有读取行的其余部分并将其存储到数组？任何优雅的方式

解决方案

  

我怎样才能做到这一点使用的BufferedReader？

您已经阅读/分割线，这样你就可以刚过输入整数其余循环，并将其添加到一个数组：

  INT []数组=新的INT [n]; //输入休息断言line.length + 2 == N; //或一些其它等效的校验的for（int i = 0; I＆LT; N;我++）
    阵列[I] =的Integer.parseInt（行第[i + 2]）;
 

这也将让你在循环中处理错误（我会留给一部分，你，你应该觉得有必要）。

in one line from the standard input I have 3 types of integers: the first integer is id, the second integer is N - some number, and after that follows N integers, separeted by a single space which I want to store in array or ArrayList. How can I do this using BufferedReader? I have the following code:

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] line = br.readLine().split(" ");
int ID = Integer.parseInt(line[0]);
int N = Integer.parseInt(line[1]);

My question is is there any elegant way to read the rest of the line and to store it into array?

解决方案

How can I do this using BufferedReader?

You've already read/split the line, so you can just loop over the rest of the inputted integers and add them to an array:

int[] array = new int[N];  // rest of the input

assert line.length + 2 == N;  // or some other equivalent check

for (int i = 0; i < N; i++)
    array[i] = Integer.parseInt(line[i + 2]);

This will also let you handle errors within the loop (I'll leave that part to you, should you find it necessary).

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