SQL 更新替换语句 [英] SQL Update Replace statement

问题描述

我需要使用 REPLACE 编写 sql 更新语句.该字符串看起来像SE*88*000000001".我需要替换两个星号*"之间的数字.除了要替换的数字总是在两个星号之间之外，这里没有其他模式.在这种情况下可以使用通配符吗?

I need to write a sql update statement using REPLACE. The string looks like 'SE*88*000000001'. I need to replace the number between the two asterisks '*'. There is no pattern here other then that number to be replaced is always between two asterisks. Is it possible to use wild cards in this situation?

感谢您的帮助.

谢谢！

推荐答案

;
WITH RowSetToUpdate AS (
  SELECT
    acolumn,
    Asterisk1Pos = CHARINDEX('*', acolumn),
    Asterisk2Pos = CHARINDEX('*', acolumn, CHARINDEX('*', acolumn) + 1)
  FROM atable
  WHERE acolumn LIKE '%*%*%'
)
UPDATE RowSetToUpdate
SET acolumn = STUFF(
  acolumn,
  Asterisk1Pos + 1,
  Asterisk2Pos - Asterisk1Pos - 1,
  'replacement_string'
)

或者如果是要替换的特定数字，那就更简单了:

Or if it's a specific number that is to be replaced, then it would be even simpler:

UPDATE atable
SET acolumn = REPLACE(acolumn, '*88*', '*replacement_string')
WHERE acolumn LIKE '%*88*%'

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