在 django/tastypie 资源中传递请求变量 [英] passing request variables in django/tastypie resources

问题描述

我需要在美味派资源中执行过滤查询.输入应该是 url 的标题，例如

I need to execute filter query inside tastypie resources. the input should be the headers of url for example

new Ext.data.Store({
   proxy: {
     url :'api/users/'
     type: "ajax",
      headers: {
       "Authorization": "1"
    }
   }
 })  

我在下面试过

from tastypie.authorization import Authorization
from django.contrib.auth.models import User
from tastypie.authentication import BasicAuthentication
from tastypie import fields
from tastypie.resources import ModelResource, ALL, ALL_WITH_RELATIONS
from tastypie.validation import Validation
from userInfo.models import ExProfile

class UserResource(ModelResource,request):
        class Meta:
            queryset = User.objects.filter(id=request.META.get('HTTP_AUTHORIZATION'))
            resource_name = 'user'
            excludes = ['email', 'password', 'is_active', 'is_staff', 'is_superuser']
            authorization = Authorization()
            authentication=MyAuthentication()

它是说name 'request' is not defined.如何在 ORM 上传递过滤器?

it is saying name 'request' is not defined. How to pass filters on ORM them?

推荐答案

不知道为什么要继承 UserResource 中的请求.

Not sure why are you inheriting request in UserResource.

我需要做这样的事情，我能想到的最佳解决方案是覆盖 dispatch 方法.像这样

I needed to do something like this and the best solution I could come up was to overwrite the dispatch method. Like this

class UserResource(ModelResource):
   def dispatch(self, request_type, request, **kwargs):
        self._meta.queryset.filter(id=request.META.get('HTTP_AUTHORIZATION'))
        return super(UserResource, self).dispatch(request_type, request, **kwargs)

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