如何添加元素在Python 3维数组 [英] How to add elements to 3 dimensional array in python

问题描述

我试图将数据存储在三维阵列即，X [0] [0] [0]蟒蛇。如何初始化的X.并增加值到它。我想这一点。

i am trying to store data in three dimensional array i.e, x[0][0][0] in python. how to initialize x. and add values to it. i tried this.

x=[]
x[0][0][0]=value1 
x[0][0].append(value1)

这两个行给予了一系列的错误。怎么做。我想它喜欢。 X [0] [0] [0] =值，X [1] [0] [0] =值2，X [0] [1] [0] =值3等如何在Python实现这一目标。

both lines are giving out of range error. how to do it. i want it like. x[0][0][0]=value1, x[1][0][0]=value2, x[0][1][0]=value3 etc. how to achieve this in python.

我期待产生这种类型的数组

i am looking to generate this kind of array

x=[[[11,[111],[112]],[12],[13]],[[21,[211],[212]],[22],[23],[24]],[[31],[32]]]
x[0][0][0] will give 11
x[1][0][0]  21
x[0][0][1] 111

等

推荐答案

我推荐使用 numpy的多维数组。这使得它更方便，速度更快。这看起来像

I recommend using numpy for multidimensional arrays. It makes it much more convenient, and much faster. This would look like

import numpy as np
x = np.zeros((10,20,30)) # Make a 10 by 20 by 30 array
x[0,0,0] = value1

不过，如果你不想使用 numpy的，或需要非矩形的多维数组，你需要把它当作列表的列表列表，并初始化每个列表：

Still, if you don't want to use numpy, or need non-rectangular multi-dimensional arrays, you will need to treat it as a list of lists of lists, and initialize each list:

x = []
x.append([])
x[0].append([])
x[0][0].append(value1)

编辑：或者你可以使用ndpu的回答显示的紧凑型符号（X = [[[值1]]]）

Or you could use the compact notation shown in ndpu's answer (x = [[[value1]]]).

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