FOSRestBundle 使用 PUT 一次只更新一个字段 [英] FOSRestBundle update only one field at a time using PUT

问题描述

之前我问过同样的问题 Symfony PUT 不包含映射的所有实体属性，我有一些#hack 解决方案来解决这个问题，但是当表单更复杂，包含选项(数组)或映射实体(对象)时，该解决方案不适用了.所以我想出了非常肮脏的想法来使它工作，例如

While ago I have asked same question Symfony PUT does not contain all entity properties mapped and I've got some #hack solution to solve the problem but when the form is more complex, contains choices (arrays) or mapped entities (objects) the solution is not applicable anymore. So I came up with very dirty ideas to make it work such as

        if(is_object($event->getForm()->getData())) $event->setData($event->getForm()->getData()->getId());
        if(is_array($event->getData()) && empty($event->getData()))
        {
            $event->setData([$event->getForm()->getData()]);
        }
        if($event->getForm()->getData() instanceof \DateTime) $event->setData($event->getForm()->getData()->format('Y-m-d H:i:s'));
        if(!is_array($event->getData()) && (is_string($event->getForm()->getData()) || is_integer($event->getForm()->getData())))
        {
            $event->setData($event->getForm()->getData());
        }

但它甚至不完美.所以我必须再问一次是否有更好的解决方案来在发送 json 响应时更新一个值，因为如果我发送 {"user":{"firstName":"John"}}属于用户表单的所有其他字段都是空的，我无法发送整个资源.我找不到任何解决此问题的方法.

but it's not even working perfect. So I must ask one more time if there's a better solution to updatejust one value at the time of sending json response, because if I send {"user":{"firstName":"John"}} all other fields belonging to the User form are empty and I cannot send entire resource. I cannot find any solution to this problem.

这里是控制器

/**
 * This endpoint updates an existing Client entity.
 *
 * @ApiDoc(
 *  resource=true,
 *  description="Updates an existing Client entity",
 * )
 * @ParamConverter("user", class="Software:User", options={"mapping": {"user": "guid"}})
 */
public function putAction(Request $request, $user)
{
    $form = $this->createForm(new UserType(['userType' => 'client', 'manager' => $this->getDoctrine()->getManager()]), $user, ['method' => 'PUT']);
    $form->handleRequest($request);

    if($form->isValid())
    {
        $manager = $this->getDoctrine()->getManager();
        $manager->flush();

        return $this->view([
            'user' => $user
        ]);
    }

    return $this->view($form);
}

推荐答案

我要回答我自己的问题.

I am going to answer my own question.

答案是使用 PATCH 方法而不是 PUT.这是修改后的代码:

The answer is to use PATCH method instead of PUT. Here's the modified code:

/**
 * This endpoint updates an existing Client entity.
 *
 * @ApiDoc(
 *  resource=true,
 *  description="Updates an existing Client entity",
 * )
 * @ParamConverter("user", class="Software:User", options={"mapping": {"user": "guid"}})
 */
public function patchAction(Request $request, $user)
{
    $form = $this->createForm(new UserType(['userType' => 'client', 'manager' => $this->getDoctrine()->getManager()]), $user, ['method' => 'PATCH']);
    $form->handleRequest($request);

    if($form->isValid())
    {
        $manager = $this->getDoctrine()->getManager();
        $manager->flush();

        return $this->view([
            'user' => $user
        ]);
    }

    return $this->view($form);
} 

请查找参考资料:Symfony2 REST API - 部分更新

http://williamdurand.fr/2012/08/02/rest-apis-with-symfony2-the-right-way/

http://williamdurand.fr/2014/02/14/please-do-not-patch-like-an-idiot/

仔细阅读 PATCH 与 PUT 章节.

Read carefully PATCH vs. PUT chapters.

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