如何从python中的上层脚本扫描脚本以获取返回值? [英] How do scan a script for return values from a upper script in python?

问题描述

import os
import pdb

os.system("ToBuildOrNot.py MSS_sims")

for output in os.system:
     if ToBuildOrNot is True:
         print "The MSS_sims Needs To rebuilt"

     elif ToBuildOrNot is False:
         print "The MSS_sism does NOT Need to be Rebuilt"

     else:
         print "error"

推荐答案

不要使用系统从 Python 脚本调用 Python 脚本，这会产生一个完整的其他解释器.只需导入它.像这样:

Don't invoke a Python script from a Python script by using system, which spawns a whole other interpreter. Just import it. Like this:

import ToBuildOrNot
needsBuild = ToBuildOrNot.run() # or whatever you call your top-level function

由于 ToBuildOrNot.py 现在是一个脚本，请确保main"函数受到保护，因此它不会在导入时自动执行.大多数人在 Python 中都是这样做的:如果 __name__ == "__main__" 会怎样:做什么?

Since ToBuildOrNot.py is a script now, make sure the "main" function is protected so it doesn't execute automatically on import. Most people do it this way in Python: What does if __name__ == "__main__": do?

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