匹配正则表达式并反转目标字符串中的匹配项 [英] Match a regex and reverse the matches within the target string

问题描述

基于这个问题 正则表达式 \d+(?:-\d+)+ 将匹配这个 10-3-1 和 5-0.

Based on this question Regex \d+(?:-\d+)+ will match this 10-3-1 and 5-0.

示例:

This is 10-3-1 my string

执行匹配和反转后，我希望它是这样的:

After performing the matching and reversing, I want it to be like this:

This is 1-3-10 my string

请注意，10-3-1 应该变成 1-3-10，而不是正常的字符串反转，这会导致 1-3-01.

Notice that 10-3-1 should become 1-3-10 and not normal string reverse which would result in 1-3-01.

推荐答案

一个基本的算法是:

1. 从字符串中提取匹配项.10-3-1"
2. 用-"字符将匹配分割成一段.
3. 您现在有一个元素列表.["10","3","1"]
4. 反转列表.["1","3","10"]
5. 使用-"字符连接数组元素.1-3-10"
6. 用新加入的字符串替换匹配项.

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