名单的二维数组在Python [英] 2d array of lists in python

问题描述

我试图让每个单元包含一个字符串列表来创建一个二维矩阵。
矩阵尺寸的创建之前是已知的，我需要存取从开始任何元件（未动态填充的矩阵）。 =>我觉得是需要某种空间preallocation的。

I am trying to create a 2d matrix so that each cell contains a list of strings. Matrix dimensions are known before the creation and I need to have access to any element from the beginning (not populating a matrix dynamically). => I think some kind of preallocation of space is needed.

例如，我想有一个2X2矩阵：

For example, I would like to have a 2X2 matrix:

[['A','B']          ['C'];
  ['d']       ['e','f','f']]

与支持传统矩阵访问操作，像

with support of traditional matrix access operations, like

(Matrix[2][2]).extend('d')

或

tmp = Matrix[2][2]
tmp.extend('d')
Matrix[2][2] = tmp

操纵与细胞的含量。

to manipulate with cells content.

如何完成它在Python？

How to accomplish it in python?

推荐答案

就像你写的：

>>> matrix = [["str1", "str2"], ["str3"], ["str4", "str5"]]
>>> matrix
[['str1', 'str2'], ['str3'], ['str4', 'str5']]
>>> matrix[0][1]
'str2'
>>> matrix[0][1] += "someText"
>>> matrix
[['str1', 'str2someText'], ['str3'], ['str4', 'str5']]
>>> matrix[0].extend(["str6"])
>>> matrix[0]
['str1', 'str2someText', 'str6']

试想一下二维矩阵列表的列表中。

Just think about 2D matrix as list of the lists.

Other operations too work just fine, like
>>> matrix[0].append('value')
>>> matrix[0]
[0, 0, 0, 0, 0, 'value']
>>> matrix[0].pop()
'value'
>>> 

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