如何做“漂亮的四舍五入"? [英] How to make "pretty rounding"?

问题描述

我需要做这样的舍入并将其转换为字符:

I need to do a rounding like this and convert it as a character:

as.character(round(5.9999,2))

我希望它变成 6.00，但它只给了我 6

I expect it to become 6.00, but it just gives me 6

无论如何我可以让它显示6.00?

Is there anyway that I can make it show 6.00?

推荐答案

尝试以下任一方法:

> sprintf("%3.2f", round(5.9999, digits=2))
[1] "6.00
> sprintf("%3.2f", 5.999)  # no round needed either
[1] "6.00

还有formatC()和prettyNum().

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