R，四舍五入，天花板和地板 [英] R, rounding, ceiling and floors

问题描述

假设有一堆从 pnorm() 返回的数据，这样你就有了 .0003ish 和 .9999ish 之间的数字.

Suppose that one has a bunch of data returned from pnorm(), such that you've got numbers between .0003ish and .9999ish.

numbers     <- round(rnorm(n = 10000, mean = 100, sd = 15))
percentiles <- pnorm(numbers, mean = 100, sd = 15)*100

然后进一步假设有人对四舍五入的百分位数感兴趣，这样 .0003 或 whatevs 将变为 1(因此天花板())，但 99.999 将变为 99(因此地板()).

And then further suppose that one is interested in rounding the percentiles such that .0003 or whatevs will come out to 1 (so ceiling()), but 99.999 will come out to 99 (so floor()).

我想我正在寻找的是 round() ，它以某种方式巧妙地知道在极端情况下将其反转，但据我所知，不存在这样的事情.我是否必须用 if 语句来丑化它?有没有更好的方法来处理这样的事情?

I guess what I'm looking for is round() that somehow brilliantly knows to reverse it in the extreme cases, but as far as I know, no such thing exists. Am I going to have to ugly it up with an if statement? Is there a better method of handling such a thing?

推荐答案

您可以使用 round 并强制将东西放入 1 或 99 在使用 pmin 和 pmax 的四肢:

You could use round and force things into 1 or 99 at the extremities using pmin and pmax:

pmax(1, pmin(99, round(percentiles)))

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