用蟒蛇围捕 [英] rounding up with python

问题描述

我已阅读以下页面:

python 小数 - 舍入到最接近的整美元(无美分)- ROUND_HALF_UP

http://docs.python.org/library/decimal.html

我有以下代码:

total_num = Decimal(str(total/10))
total_num.quantize(Decimal('1'), rounding=ROUND_UP)

但它总是四舍五入?所以如果我有 221，我希望它返回 23.现在我得到 22.我对此有什么误解吗?

But its always rounding down? So if I have 221, I want it to return 23. Right now I'm getting 22. Is there something I'm misunderstanding regarding this?

我将其更改为以下内容:total_num = int(math.ceil(float(total)/10))

I changed it to the following: total_num = int(math.ceil(float(total)/10))

我需要一个 int 来继续具有 range 的 for 循环.

I needed an int to continue with the for loop that has a range.

推荐答案

你不能使用 math.ceil 吗?如果您使用浮点除法，它将做必要的事情.目前你正在做一个整数除法.

Can't you use math.ceil? It will do the necessary thing if you are using a float division. Currently you are doing an integer division.

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