将命名列表向量从 R 翻译成 Python 中的 rpy2? [英] translating named list vectors from R into rpy2 in Python?

问题描述

python 中 Rpy2 中以下 R 代码的等价物是什么?

What is the equivalent of the following R code in Rpy2 in python?

Var1 = c("navy", "darkgreen")
names(Var1) = c("Class1", "Class2")
ann_colors = list(Var1 = Var1)

不清楚 ann_colors 是什么.在 R 中评估时，它给出:

It's not clear what ann_colors is. When evaluated in R it gives:

> ann_colors
$Var1
     Class1      Class2 
     "navy" "darkgreen" 

它是一个 robject.ListVector 吗?我试过了:

Is it an robject.ListVector? I tried:

robjects.ListVector({"Class1": "navy", "Class2": "green"})

但不完全是因为我不知道如何告诉 ListVector 对象这个对象的名称是 Var1，即类似于 list(Var1 = Var1).

but it's not quite it because I'm not sure how to tell the ListVector object that the name of this object is Var1, i.e. something like list(Var1 = Var1).

如何将其正确转换为 rpy2?

How can this be properly translated to rpy2?

推荐答案

经过数小时的反复试验，我找到了解决方案.我不完全理解为什么类似的变体不起作用，或者为什么这个方案不能与数据帧互换，但我要做的是:

After many hours of trial and error, I found the solution. I don't fully understand why the similar variants of this did not work, or why this scheme is not interchangeable with dataframes, but what I got to work is:

anno_colors = robj.StrVector(tuple(["navy", "green"]))
anno_colors.names = ["Class1", "Class2"]
od = OrderedDict()
od["Type"] = anno_colors
result = robj.ListVector(od)
print str(result)

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