如何在 rpy2 中将列表传递给 R 并返回结果 [英] How to pass a list to R in rpy2 and get result back

问题描述

我第一次尝试使用 rpy2.假设我在 python 中有一个列表

I am trying to use rpy2 for the first time. Let's say I have in python a list

l = [1,2,3,4,5,6]

我想在 R 中调用

ks.test(l, pexp)

我该怎么做?

我最初的尝试是

#!/usr/bin/python
import rpy2.robjects as robjects

l = [1,2,3,4,5]

f = robjects.r('''
f<-function(l){
    ks.test(l, pexp)
}''')
print f(l)

这显然不是正确的做法

Error in sort.int(x, na.last = na.last, decreasing = decreasing, ...) : 
  'x' must be atomic
Traceback (most recent call last):
  File "./rpy2-test.py", line 12, in <module>
    print f(l)
  File "/usr/local/lib/python2.7/dist-packages/rpy2/robjects/functions.py", line 166, in __call__
    return super(SignatureTranslatedFunction, self).__call__(*args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/rpy2/robjects/functions.py", line 99, in __call__
    res = super(Function, self).__call__(*new_args, **new_kwargs)
rpy2.rinterface.RRuntimeError: Error in sort.int(x, na.last = na.last, decreasing = decreasing, ...) : 
  'x' must be atomic

这样做的正确方法是什么?

What is the right way to do this?

推荐答案

我认为您不能直接将 Python 列表传递给 R.您可以在使用之前转换为 R int 向量.

I don't think you can pass a python list to R directly. You can convert to a R int vector before use it.

#!/usr/bin/python
import rpy2.robjects as robjects

l = [1,2,3,4,5]

# get ks.test via execute string as R statement
test = robjects.r('ks.test')
# get a built-in functions variables directly
pexp = robjects.r.pexp

l_vector = robjects.IntVector(l)
result = test(l_vector, pexp)
print result[result.names.index('p.value')]

参考:

• 使用 R 的 OOP
• 函数
• 向量和数组

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