如何在没有 any_instance 的情况下断言未进行方法调用? [英] How to assert that a method call was not made, without any_instance?

问题描述

我有一个类，在一种情况下应该调用:my_method，但在另一种情况下不能调用方法:my_method.我想测试这两种情况.另外，我希望测试记录不应该调用 :my_method 的情况.

I have a class, that in one situation should call :my_method, but in another situation must not call method :my_method. I would like to test both cases. Also, I would like the test to document the cases when :my_method should not be called.

使用any_instance 通常不鼓励，所以我很乐意学习一个很好的方法来替换它.

Using any_instance is generally discouraged, so I would be happy to learn a nice way to replace it.

这个代码片段是我想要编写的测试类型的简化示例.

This code snippet is a reduced example on what I kind of test I would like to write.

class TestSubject
  def call
    call_me
  end

   def call_me; end
   def never_mind; end
end

require 'rspec'

spec = RSpec.describe 'TestSubject' do
  describe '#call' do
    it 'calls #call_me' do
      expect_any_instance_of(TestSubject).to receive(:call_me)
      TestSubject.new.call
    end

    it 'does not call #never_mind' do
      expect_any_instance_of(TestSubject).not_to receive(:never_mind)
      TestSubject.new.call
    end
  end
end

spec.run # => true

它有效，但使用了 expect_any_instance_of 方法，不推荐使用.

It works, but uses expect_any_instance_of method, which is not recommended.

如何更换?

推荐答案

我会做类似的事情

describe TestSubject do
  describe '#call' do
    it 'does not call #something' do 
      subject = TestSubject.new
      allow(subject).to receive(:something)

      subject.call

      expect(subject).not_to have_received(:something)
    end
  end
end

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