使用 XSLT 设置 RSS 提要样式，CDATA 标签问题 [英] Styling RSS feed using XSLT, issues with CDATA tags
问题描述
我正在为 RSS 提要设置样式，但在以下部分存在问题:
I am styling an RSS feed but having an issue with the following part:
<description>
<![CDATA[
<img src="http://l.yimg.com/a/i/us/we/52/34.gif"/><br /> <b>Current Conditions:</b><br /> Fair, 73 F<BR /> <BR /><b>Forecast:</b><BR /> Sat - Clear. High: 78 Low: 62<br /> Sun - Mostly Sunny. High: 80 Low: 66<br /> <br /> <a href="http://us.rd.yahoo.com/dailynews/rss/weather/Dubai__AE/*http://weather.yahoo.com/forecast/AEXX0004_f.html">Full Forecast at Yahoo! Weather</a><BR/><BR/> (provided by <a href="http://www.weather.com" >The Weather Channel</a>)<br/>
]]>
</description>
您可以在此处
这是我的 XSLT:
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<head>
<title></title>
</head>
<body>
<table cellpadding="2" cellspacing="0" border="0" width="75%">
<xsl:for-each select="rss/channel/item">
<tr style="color:#0080FF;">
<td style="text-align:left;font-weight:bold;">
<xsl:value-of select ="title"></xsl:value-of>
</td>
</tr>
<tr style="color:#0080FF;">
<td style="text-align:left;font-weight:bold;">
<xsl:value-of select ="location"></xsl:value-of>
<xsl:value-of select="pubDate"/>
</td>
</tr>
<tr>
<td colspan="2" style="text-align:left;padding-top:10px;">
<xsl:value-of select="description"/>
</td>
</tr>
<tr>
<td colspan="2" style="height:20px;">
<hr></hr>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
我试图从描述标签中获取信息，这样我就可以像标题和出版日期一样设置样式.这里是我正在尝试设置样式的完整 XML RSS 提要.谁能帮我弄清楚为什么 CDATA 标签会搞砸?
I am trying to get the information from the description tag so I can style it like I did the title and publication date. Here is the full XML RSS feed which I am trying to style. Can anyone help me figure out why the CDATA tags are messing things up?
推荐答案
尽量不要使用
Try not to use <xsl:for-each>. Code becomes more clearly arranged when you rely on <xsl:template> and <xsl:apply-templates>.
还尝试使用 CSS 类并从输出 HTML 中删除内联样式.
Also try to use CSS classes and remove the inline style from the output HTML.
如果您输出经典的 HTML(不是 XHTML)，那么使用 <xsl:output> 告诉 XSLT 处理器并输出一个文档类型.
If you output classic HTML (not XHTML) then tell the XSLT processor so by using <xsl:output> and also output a doctype.
您的输出问题将通过使用 disable-output-escaping="yes" 来解决.请注意，并非每个 XSL 处理器都支持该属性.根据 XSLT 规范，禁用输出转义的能力是可选的.
Your output problem will be solved by using disable-output-escaping="yes". Note that not every XSL processor supports that attribute. The ability to disable output escaping is optional as per the XSLT spec.
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
<xsl:output method="html" indent="yes"
doctype-system='http://www.w3.org/TR/html4/strict.dtd'
doctype-public='-//W3C//DTD HTML 4.01//EN'
/>
<xsl:template match="/rss">
<html>
<head>
<title></title>
</head>
<body>
<xsl:apply-templates select="channel" />
</body>
</html>
</xsl:template>
<xsl:template match="channel">
<table cellpadding="2" cellspacing="0" border="0" width="75%">
<xsl:apply-templates select="item" />
</table>
</xsl:template>
<xsl:template match="item">
<!-- ... -->
<tr>
<td colspan="2" style="text-align:left;padding-top:10px;">
<xsl:value-of select="description" disable-output-escaping="yes" />
</td>
</tr>
<!-- ... -->
</xsl:template>
</xsl:stylesheet>
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