搜索一个数组的值，但只打印一审[更新] [英] Searching an array for a value but only printing the first instance[update]
问题描述
我想提出一个赛马程序将打印1日2次和第3名的马匹。我要成立的10匹马中的数组，然后从1-3到自己的位置添加随机数。获胜者是先马打15或更高。
我的问题是我的程序不能正常打印的第二和第三位的马匹。
[更新]我去掉了很多条件，并添加字符串变量来存储信息。它运行顺畅，但现在我不知道为什么程序不断重复印刷等和
下面是code，我更新了为循环被打印获奖者：
进口的java.util。*;
公共类赛马{
公共静态无效的主要（字串[] ARG）{
扫描仪读卡器=新的扫描仪（System.in）;
INT范围= 3;
INT赢= 15;
最终诠释SIZE = 5;
随机RAN =新的随机（）;
布尔赢家= FALSE;
布尔秒= FALSE;
INT [] = arrRan新INT [SIZE] System.out.print（去比赛preSS输入，使马跑！）; 串readString = reader.nextLine（）;
而（赢家！= TRUE）{//永远循环下去，直到赢家
//程序开始
System.out.print（readString）;
如果（readString.equals（））{//进入时是pressed 的for（int i = 0; I＆LT; arrRan.length;我++）{//循环进入时，增加的位置是pressed
arrRan [I] = arrRan [I] +（ran.nextInt（3）+ 1）; //添加到随机数阵列
的System.out.println（马+第（i + 1）+：+ arrRan [I]）; //打印数组的内容
}
}//万一
如果（reader.hasNextLine（））{
readString = reader.nextLine（）;
的System.out.println（请preSS输入。）;
}
的for（int i = 0; I＆LT; arrRan.length;我++）{
如果（arrRan [I]＆GT; = 15）{//如果一个胜利者被发现
第一=第一+马+（I + 1）+;
赢家= TRUE; } //如果获奖者被发现，然后寻找一个亚军
//如果没有第14位再搜索13，如果没有13那么12最低第二名将在第12位。
如果（arrRan [Ⅰ] == 14）{
第二= +二马+（I + 1）+;
secondPl = TRUE; }
如果（arrRan [I] = 14＆安培;！＆安培; arrRan [I] == 13）{
第二= +二马+（I + 1）+;
secondPl = TRUE;
}
如果（arrRan [I] = 13安培;！＆安培; arrRan [I] == 12）{
第二= +二马+（I + 1）+;
secondPl = TRUE;
}
如果（arrRan [Ⅰ] == 13）{
第三=第三+马+（I + 1）+;
}
}
如果（冠军==真）{
的System.out.println（第一）;
的System.out.println（第二）;
的System.out.println（第三）;
} } //结束时
} //关闭主
} //关闭类
您可以从为循环使用破退出语句。
I am making a horse race program that will print the 1st 2nd and 3rd place horses. I have to set up the 10 horses in an array and then add random number from 1-3 to their position. The winner is the first horse to hit 15 or beyond.
My problem is that my program does not properly print the 2nd and 3rd place horses.
[UPDATE] I removed the many conditions and added string variables to store the information. It runs smoother but now I dont know why the program keeps printing duplicates and such.
Here is the code, I updated the for loop that was printing the winners:
import java.util.*;
public class HorseRace{
public static void main(String[ ] arg){
Scanner reader = new Scanner(System.in);
int range = 3;
int win = 15;
final int SIZE = 5;
Random ran = new Random( );
boolean winner = false;
boolean second = false;
int[ ] arrRan = new int[SIZE];
System.out.print("Off to the races! Press enter to make the horses run.");
String readString = reader.nextLine();
while(winner!=true){//loop forever until winner
//begin program
System.out.print(readString);
if(readString.equals("")){//when enter is pressed
for(int i = 0; i<arrRan.length; i++){//loop that adds position when enter is pressed
arrRan[i] = arrRan[i] + (ran.nextInt(3) + 1); //add to the array in random numbers
System.out.println("Horse " + (i+1) + ": " + arrRan[i]);//print the contents of the array
}
}//end if
if(reader.hasNextLine()){
readString = reader.nextLine();
System.out.println("Please press enter.");
}
for(int i = 0; i<arrRan.length; i++){
if(arrRan[i]>=15){//if a winner is found
first = first + "Horse " + (i+1)+" ";
winner = true;
}
//if winner is found then look for a 2nd place
//if there is no position 14 then search for 13, if no 13 then 12. The lowest 2nd place will be in position 12.
if(arrRan[i]==14){
second = second + "Horse " + (i+1)+" ";
secondPl = true;
}
if(arrRan[i]!=14&&arrRan[i]==13){
second = second + "Horse " + (i+1)+" ";
secondPl = true;
}
if(arrRan[i]!=13&&arrRan[i]==12){
second = second + "Horse " + (i+1)+" ";
secondPl = true;
}
if(arrRan[i]==13){
third = third + "Horse " + (i+1)+" ";
}
}
if(winner==true){
System.out.println(first);
System.out.println(second);
System.out.println(third);
}
}//end while
}//close main
}//close class
You can exit from a for loop using the break statement.
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