拆分字符串时如何避免删除尾随空项目? [英] How do I avoid trailing empty items being removed when splitting strings?

问题描述

我在做:

"b::::c:::".split(':')

结果:

["b", "", "", "", "c", "", ""] # expect
["b", "", "", "", "c"] # actual

这里有什么问题?我怎样才能得到我所期望的.

What is the problem here? how can i get what i expected.

推荐答案

.split(pattern=$;, [limit]) 有一个 limit 参数.如果省略 limit，则抑制尾随空字段.您需要提供一个负 limit

There's a limit parameter to .split(pattern=$;, [limit]). If limit is omitted, trailing null fields are suppressed. You need to provide a negative limit

"b::::c:::".split(':', -1) 

但请记住，这将在数组末尾返回三个 "" 值.

but bear in mind that this will return three "" values at the end of the array.

result: ["b", "", "", "", "c", "", "", ""] 

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