如何获得符号链接的目标? [英] How do I get the target of a symlink?

问题描述

我有一个字符串，其中包含现有符号链接的文件系统路径.我想得到这个链接指向的路径.

I have a string containing the file system path to an existing symlink. I want to get the path that this link points to.

基本上我想要的东西和我能通过这点黑客一样:

Basically I want the same that I'd get through this bit of hackery:

s = "path/to/existing/symlink"
`ls -ld #{s}`.scan(/-> (.+)/).flatten.last

但我想在不花钱的情况下做到这一点.

but I want to do it without shelling out.

推荐答案

我认为 readlink 就是您要查找的内容:

I think readlink is what you are looking for:

File.readlink("path/to/symlink")

这篇关于如何获得符号链接的目标?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！