测试变量是否等于两个值之一 [英] Test whether a variable equals either one of two values

问题描述

我想测试 a 是否等于 1 或 2

I want to test whether a equals 1 or 2

我能做到

a == 1 || a == 2

但这需要重复a(这对于较长的变量会很烦人)

but this requires repeating a (which would be annoying for longer variables)

我想做a == (1 || 2)之类的事情，但显然这行不通

I'd like to do something like a == (1 || 2), but obviously this won't work

我可以做 [1, 2].include?(a)，这还不错，但让我觉得有点难以阅读

I could do [1, 2].include?(a), which is not bad, but strikes me as a bit harder to read

只是想知道如何用惯用的 ruby​​ 做到这一点

Just wondering how do to this with idiomatic ruby

推荐答案

您的第一个方法是惯用的 Ruby.不幸的是，Ruby 没有与 Python 的 a in [1,2] 等效，我认为它会更好.你的 [1,2].include?a 是最接近的选择，我认为它与最自然的方式有点倒退.

Your first method is idiomatic Ruby. Unfortunately Ruby doesn't have an equivalent of Python's a in [1,2], which I think would be nicer. Your [1,2].include? a is the nearest alternative, and I think it's a little backwards from the most natural way.

当然，如果你经常使用它，你可以这样做:

Of course, if you use this a lot, you could do this:

class Object
  def member_of? container
    container.include? self
  end
end

然后你可以做a.member_of?[1, 2].

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