我如何得到这个二维数组，以向右旋转90度？ [英] How do I get this 2D Array to rotate to the right 90 degrees?

问题描述

所以，我有一个二维数组，并且它应该是向右旋转90度，而是它旋转到左边。实在想不通，为什么

公共类裂缝$ C $ {C16

 公共静态无效的主要（字符串ARGS []）{
    INT [] [] oldarray =新INT [3] [3];    int值= 1;    的for（int i = 0;我3;;我++）{
        为（中间体J = 0; J＆下; 3; J ++）{
            oldarray [I] [J] =价值;
            价值++;
        }
    }
    的for（int i = 0;我3;;我++）{
        为（中间体J = 0; J＆下; 3; J ++）{
            System.out.print（oldarray [I] [J] +\\ t的）;
        }
        的System.out.println（）;
    }
    oldarray =旋转（oldarray，3）;
    的System.out.println（）;
    的for（int i = 0;我3;;我++）{
        为（中间体J = 0; J＆下; 3; J ++）{
            System.out.print（oldarray [I] [J] +\\ t的）;
        }
        的System.out.println（）;
    }}公共静态INT [] []旋转（INT [] [] passedIn，INT N）{    INT [] [] newarray =新的INT [n] [n]的;    的for（int i = 0; I＆LT; N;我++）{
        对于（INT J = 0; J＆LT; N; J ++）{
            newarray [I] [j]的= passedIn [j]的[n-1个-1];
        }
    }    返回newarray;
}
 

}

输出：

1 2 3结果
4 5 6结果
7 8 9

3 6 9结果
2 5 8结果
1 4 7

解决方案

  newArray [I] [J] = passedIn [N-1-J] [I];
 

而不是

  newarray [I] [J] = passedIn [J] [N-1-I]
 

此外，与Java8工作时，你可能会考虑使用流来打印数组：

  Stream.of（oldarray）.forEach（E  - ＆GT;的System.out.println（Arrays.toString（E）））;
 

So I have a 2D array, and it is supposed to rotate to the right 90 degrees, but instead it rotates to the left. Really can't figure out why

public class CrackCode16 {

public static void main (String args[]){
    int [] [] oldarray = new int [3][3];

    int value = 1;

    for (int i = 0; i < 3; i++){
        for (int j =0; j<3; j++){
            oldarray[i][j] = value;
            value++;
        }
    }


    for (int i = 0; i < 3; i++){
        for (int j =0; j<3; j++){
            System.out.print(oldarray[i][j] + "\t");
        }
        System.out.println("");
    }


    oldarray = rotate(oldarray, 3);


    System.out.println("");
    for (int i = 0; i < 3; i++){
        for (int j =0; j<3; j++){
            System.out.print(oldarray[i][j] + "\t");
        }
        System.out.println("");
    }

}

public static int [][] rotate (int [][] passedIn, int n){

    int [][] newarray = new int [n][n];

    for (int i = 0; i < n; i++){
        for (int j =0; j<n; j++){
            newarray[i][j] = passedIn [j][n-1-i];
        }
    }   

    return newarray;
}

}

Output:

1 2 3
4 5 6
7 8 9

3 6 9
2 5 8
1 4 7

解决方案

newArray[i][j] = passedIn [n-1-j][i];

instead of

newarray[i][j] = passedIn [j][n-1-i];

Additionally, when working with Java8, you might consider using a Stream to print your array:

Stream.of(oldarray).forEach(e -> System.out.println(Arrays.toString(e)));

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