在 ruby 中反转数组的顺序 [英] reversing the order of an array in ruby
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问题描述
我有以下数组 [12,16,5,9,11,5,4] 它打印: 12,16,5,9,11,5,4.
I have the following array [12,16,5,9,11,5,4] it prints: 12,16,5,9,11,5,4.
我想让它打印:4,5,11,9,5,16,12
当我执行 array.reverse 时，它打印:
When I did array.reverse it printed:
4,5,11,9,5,61,21
它反转了单个数字 - 知道我怎么能阻止它吗?
It reversed individual numbers - any idea how I can stop that?
推荐答案
irb(main):001:0> a = [12,16,5,9,11,5,4]
=> [12, 16, 5, 9, 11, 5, 4]
irb(main):002:0> a.reverse
=> [4, 5, 11, 9, 5, 16, 12]
我没有看到你所看到的.
I'm not seeing what you're seeing.
编辑:扩展 Ben 注意到的内容，您可能正在反转字符串.
Edit: Expanding on what Ben noticed, you may be reversing a string.
irb(main):005:0> "12,16,5,9,11,5,4".reverse
=> "4,5,11,9,5,61,21"
如果您必须以这种方式反转字符串，您应该执行以下操作:
If you have to reverse a string in that manner, you should do something like the following:
irb(main):008:0> "12,16,5,9,11,5,4".split(",").reverse.join(",")
=> "4,5,11,9,5,16,12"
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