将 Ruby 中的字符串切成固定长度的字符串，忽略(不考虑/不管)新行或空格字符 [英] Chop a string in Ruby into fixed length string ignoring (not considering/regardless) new line or space characters

问题描述

我有一个包含许多新行和空格的字符串.我需要将其拆分为固定长度的子字符串.例如

I have a string containing many new line and spaces. I need to split it into fixed length sub strings. E.g

a = "This is some\nText\nThis is some text"

现在我想把它分成长度为 17 的字符串.所以现在它应该导致

And now i would like to split it into say strings of length 17. so now it should result in

["This is some\nText", "\nThis is some tex", "t"]

注释:我的字符串可能包含任何字符(空格/单词等)

Comment: My string may contain any character (white space/word etc)

推荐答案

"This is some\nText\nThis is some text".scan(/.{1,17}/m)
# => ["This is some\nText", "\nThis is some tex", "t"]

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