如果值超出范围，则返回最小值/最大值的 Ruby 优雅方式 [英] Ruby Elegant Way to Return Min/Max if Value Outside Range

问题描述

所以我正在编写一个程序来为流程建模并需要计算费用.逻辑是，如果费用金额小于最低金额，则使用最低金额，如果费用金额大于最高金额，则使用最高金额.

So I am writing a program to model a process and need to calculate fees. The logic is that if the fee amount is less than a minimum use the minimum and if the fee amount is greater than the maximum use the maximum.

我当然可以在多行上实现这一点，但我很想知道在 Ruby 中是否有更优雅的方法来做到这一点.

I can of course make this happen on multiple lines but would be interested to know if there is a more elegant way to do this in Ruby.

fee_amount = <whatever logic I need>
if fee_amount < min return min
if fee_amount > max return max
return fee_amount

推荐答案

如果只是一个场合，我会推荐 Shawn Balestracci 的答案，这是最漂亮的.

If it is just for one occasion, I would recommend Shawn Balestracci's answer, which is the most beautiful.

或者，以下是我个人库中的一些方法:

Alternatively, here are some methods from my personal library:

module Comparable
  def at_least other; self < other ? other : self end
  def at_most other; self > other ? other : self end
end

我是这样使用的:

fee_amount = <whatever logic I need>.at_least(min).at_most(max)

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