按 ruby 中的值对哈希进行分组 [英] Group Hash by values in ruby
本文介绍了按 ruby 中的值对哈希进行分组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在 ruby 中有一个散列,看起来像这样:
I have a hash in ruby which looks something like this:
{
"admin_milestones"=>"1",
"users_milestones"=>"0",
"admin_goals"=>"1",
"users_goals"=>"0",
"admin_tasks"=>"1",
"users_tasks"=>"0",
"admin_messages"=>"1",
"users_messages"=>"0",
"admin_meetings"=>"1",
"users_meetings"=>"0"
}
我正在寻找一种解决方案,可以将这个散列分成两部分,一个值为 1,另一个散列值为 0.
I am trying to lookout for a solutions which can cut this hash in to two parts, one with value as 1 and other hash with value as 0.
推荐答案
您可以按哈希值分组:
h1 = {
"admin_milestones"=>"1",
"users_milestones"=>"0",
"admin_goals"=>"1",
"users_goals"=>"0",
"admin_tasks"=>"1",
"users_tasks"=>"0",
"admin_messages"=>"1",
"users_messages"=>"0",
"admin_meetings"=>"1",
"users_meetings"=>"0"
}
h2 = h1.group_by{|k,v| v}
它将产生一个按其值分组的散列,如下所示:
It will produce a hash grouped by its values like this:
h2 = {"1"=>[["admin_milestones", "1"], ["admin_goals", "1"], ["admin_tasks", "1"], ["admin_messages", "1"], ["admin_meetings", "1"]],
"0"=>[["users_milestones", "0"], ["users_goals", "0"], ["users_tasks", "0"], ["users_messages", "0"], ["users_meetings", "0"]]}
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