我将如何将此时间字符串转换为 ruby​​ 中的纪元时间? [英] How would I go about converting this time string to epoch time in ruby?

问题描述

我将如何将 2012-12-13T14:43:35.371Z 转换为纪元时间?

How would I go about converting 2012-12-13T14:43:35.371Z to epoch time?

我正在考虑的一种方法是去除 T 和 Z，然后尝试使用 DateTime 库找到一种转换为纪元的方法.在我走这条路之前，我很好奇是否有一个宝石可以用来快速完成这项工作.在相关说明中，我将在转换为纪元后进行时间计算.

One approach I was considering was to strip the T and Z and then try to use the DateTime library to find a way to convert to epoch. Before I go down that path, I was curious if there is a gem I could use to do this quickly. On a related note, I will be doing time calculations after I convert to epoch.

推荐答案

例如:

require 'date'

# as an integer:
DateTime.parse('2012-12-13T14:43:35.371Z').to_time.to_i
# or as a string:
DateTime.parse('2012-12-13T14:43:35.371Z').strftime('%s')

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