都做吗?有吗?保证短路评估? [英] Do all? and any? guarantee short-circuit evaluation?
问题描述
在 pry
和 irb
中测试一些代码,我得到以下结果:
Testing out some code in both pry
and irb
, I get the following results:
[1] pry(main)> a = [1, 3, 5, 7, 0]
=> [1, 3, 5, 7, 0]
[2] pry(main)> a.any? {|obj| p obj; 3 / obj > 1}
1
=> true
[3] pry(main)> a.all? {|obj| p obj; 3 / obj > 1}
1
3
=> false
在 [2]
和 [3]
我看到似乎有短路评估会尽快中止迭代,但这是有保证的行为吗?阅读文档没有提到这种行为.我意识到我可以使用 inject
代替,因为它会遍历所有内容,但我很想知道官方的 Ruby 视图是什么.
In [2]
and [3]
I see that there appears to be short-circuit evaluation that aborts the iteration as soon as possible, but is this guaranteed behaviour? Reading the documentation there is no mention of this behaviour. I realise that I can use inject
instead as that will iterate over everything, but I'm interested in finding out what the official Ruby view is.
推荐答案
是.
在 Ruby 标准的最终草案中,all?
定义如下:
In the final draft of the Ruby standard, all?
is defined as such:
- 在接收器上调用
each
方法 - 对于方法
each
产生的每个元素 X:
- Invoke the method
each
on the receiver - For each element X which the method
each
yeilds:
- 如果给出了块,则以 X 作为参数调用块.如果这个调用返回一个虚假的对象,return false.
- 如果块没有给出,并且 X 是一个虚假的对象,返回 false.
注意步骤 2 中的 return 这个词.这保证了短路评估.any?
的定义类似.然而,该标准仍然是一个草案,我不知道哪些 Ruby 实现(如果有)旨在符合标准.
Note the word return in step 2. This guarantees short circuit evaluation. any?
is defined similarly. However the standard is still a draft and I don't know which Ruby implementations (if any) aim to be standards-compliant.
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