如何跨新行拆分字符串并保留空行? [英] How to split string across new lines and keep blank lines?

问题描述

给定红宝石代码:

"aaaa\nbbbb\n\n".split(/\n/)

输出:

["aaaa", "bbbb"] 

我希望输出包含由 \n\n 指示的空行——我希望结果是:

I would like the output to include the blank line indicated by \n\n -- I want the result to be:

["aaaa", "bbbb", ""]

获得准确结果的最简单/最好的方法是什么?

What is the easiest/best way to get this exact result?

推荐答案

对于此任务，我建议使用 lines 而不是 split.lines 将保留尾随换行符，这样您就可以看到所需的空行.使用chomp清理:

I'd recommend using lines instead of split for this task. lines will retain the trailing line-break, which allows you to see the desired empty-line. Use chomp to clean up:

"aaaa\nbbbb\n\n".lines.map(&:chomp)
[
    [0] "aaaa",
    [1] "bbbb",
    [2] ""
]

<小时>

其他更复杂的方法是:

---

Other, more convoluted, ways of getting there are:

"aaaa\nbbbb\n\n".split(/(\n)/).each_slice(2).map{ |ary| ary.join.chomp }
[
    [0] "aaaa",
    [1] "bbbb",
    [2] ""
]

它利用了在 split 中使用捕获组的优势，它返回带有被分割的中间文本的分割文本.each_slice 然后将元素分组为两个元素的子数组.map 获取每个两个元素的子数组，在 join 之后是 chomp.

It's taking advantage of using a capture-group in split, which returns the split text with the intervening text being split upon. each_slice then groups the elements into two-element sub-arrays. map gets each two-element sub-array, does the join followed by the chomp.

或者:

"aaaa\nbbbb\n\n".split(/(\n)/).delete_if{ |e| e == "\n" }
[
    [0] "aaaa",
    [1] "bbbb",
    [2] ""
]

以下是 split 返回的内容:

Here's what split is returning:

"aaaa\nbbbb\n\n".split(/(\n)/)
[
    [0] "aaaa",
    [1] "\n",
    [2] "bbbb",
    [3] "\n",
    [4] "",
    [5] "\n"
]

我们不经常使用它，但它可能很有用.

We don't see that used very often, but it can be useful.

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