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ActiveModel - 视图 - Rails 中的控制器而不是 ActiveRecord?
[英] ActiveModel - View - Controller in Rails instead of ActiveRecord?
本文介绍了ActiveModel - 视图 - Rails 中的控制器而不是 ActiveRecord?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在尝试对我的模型使用 ActiveModel 而不是 ActiveRecord，因为我不希望我的模型与数据库有任何关系.
以下是我的模型:
类用户包括 ActiveModel::Validations验证 :name, :presence =>真的验证 :email, :presence =>真的验证 :password, :presence =>真，:确认 =>真的attr_accessor :name, :email, :password, :saltdef 初始化(属性 = {})@name = 属性[:name]@email = 属性[:email]@password = 属性[:密码]@password_confirmation = 属性[:password_confirmation]结尾结尾
这是我的控制器:
class UsersController <应用控制器定义新@user = User.new@title = "注册"结尾结尾
我的观点是:
注册
<%= form_for(@user) do |f|％＞<div class="field"><%= f.label :name %><br/><%= f.text_field :name %>
<div class="field"><%= f.label :email %><br/><%= f.text_field :email %>
<div class="field"><%= f.label :password %><br/><%= f.password_field :password %>
<div class="field"><%= f.label :password_confirmation, "Confirmation" %><br/><%= f.password_field :password_confirmation %>
<div class="actions"><%= f.submit "注册" %>
<%结束%>
但是当我在浏览器中加载此视图时，出现异常:
用户未定义的方法to_key":0x104ca1b60
有人可以帮我解决这个问题吗?
非常感谢！
解决方案
我翻遍了 Rails 3.1 源代码来解决这个问题，我认为这比搜索其他任何地方都容易.早期版本的 Rails 应该是类似的.如果 tl;dr.
，则跳到最后<小时>
当你调用 form_for(@user) 时，你会经历这个:
def form_for(record, options = {}, &proc)#...案例记录当字符串，符号object_name = 记录对象 = 零别的object = record.is_a?(Array) ?record.last : 记录object_name = options[:as] ||ActiveModel::Naming.param_key(object)apply_form_for_options!(记录，选项)结尾
而且由于 @user 既不是字符串也不是对象，您可以通过 else 分支进入 apply_form_for_options!.在 apply_form_for_options! 中，我们看到:
as = options[:as]#...options[:html].reverse_merge!(:class =>作为 ?"#{as}_#{action}" : dom_class(object, action),:id =>作为 ?"#{as}_#{action}" : dom_id(object, action),:方法 =>方法)
注意那段代码，它包含问题的根源和解决方案.dom_id 方法调用 record_key_for_dom_id 如下所示:
def record_key_for_dom_id(record)record = record.to_model if record.respond_to?(:to_model)键 = record.to_key钥匙 ?sanitize_dom_id(key.join('_')) : 键结尾
还有您对 to_key 的调用.to_key 方法由 ActiveRecord::AttributeMethods::PrimaryKey<定义/code> 并且由于您没有使用 ActiveRecord，因此您没有 to_key 方法.如果您的模型中有一些类似于主键的东西，那么您可以定义自己的 to_key 并保留它.
但是，如果我们回到apply_form_for_options！，我们会看到另一个解决方案:
as = options[:as]
因此，您可以为 form_for 提供 :as 选项以手动为您的表单生成 DOM ID:
<%= form_for(@user, :as => 'user_form') do |f|％＞
不过，您必须确保 :as 值在页面中是唯一的.
<小时>
执行摘要:
- 如果您的模型具有类似于主键的属性，则定义您自己的返回它的
to_key 方法. - 或者，为
form_for 提供适当的 :as 选项.
I'm trying to use ActiveModel instead of ActiveRecord for my models because I do not want my models to have anything to do with the database.
Below is my model:
class User
include ActiveModel::Validations
validates :name, :presence => true
validates :email, :presence => true
validates :password, :presence => true, :confirmation => true
attr_accessor :name, :email, :password, :salt
def initialize(attributes = {})
@name = attributes[:name]
@email = attributes[:email]
@password = attributes[:password]
@password_confirmation = attributes[:password_confirmation]
end
end
And here's my controller:
class UsersController < ApplicationController
def new
@user = User.new
@title = "Sign up"
end
end
And my view is:
<h1>Sign up</h1>
<%= form_for(@user) do |f| %>
<div class="field">
<%= f.label :name %><br />
<%= f.text_field :name %>
</div>
<div class="field">
<%= f.label :email %><br />
<%= f.text_field :email %>
</div>
<div class="field">
<%= f.label :password %><br />
<%= f.password_field :password %>
</div>
<div class="field">
<%= f.label :password_confirmation, "Confirmation" %><br />
<%= f.password_field :password_confirmation %>
</div>
<div class="actions">
<%= f.submit "Sign up" %>
</div>
<% end %>
But when I load this view in the browser, I am getting an exception:
undefined method 'to_key' for User:0x104ca1b60
Can anyone please help me with this?
Many thanks in advance!
解决方案
I went rooting around the Rails 3.1 source to sort this out, I figured that would be easier than searching anywhere else. Earlier versions of Rails should be similar. Jump to the end if tl;dr.
When you call form_for(@user), you end going through this:
def form_for(record, options = {}, &proc)
#...
case record
when String, Symbol
object_name = record
object = nil
else
object = record.is_a?(Array) ? record.last : record
object_name = options[:as] || ActiveModel::Naming.param_key(object)
apply_form_for_options!(record, options)
end
And since @user is neither a String nor Object, you go through the else branch and into apply_form_for_options!. Inside apply_form_for_options! we see this:
as = options[:as]
#...
options[:html].reverse_merge!(
:class => as ? "#{as}_#{action}" : dom_class(object, action),
:id => as ? "#{as}_#{action}" : dom_id(object, action),
:method => method
)
Pay attention to that chunk of code, it contains both the source of your problem and the solution. The dom_id method calls record_key_for_dom_id which looks like this:
def record_key_for_dom_id(record)
record = record.to_model if record.respond_to?(:to_model)
key = record.to_key
key ? sanitize_dom_id(key.join('_')) : key
end
And there's your call to to_key. The to_key method is defined by ActiveRecord::AttributeMethods::PrimaryKey and since you're not using ActiveRecord, you don't have a to_key method. If you have something in your model that behaves like a primary key then you could define your own to_key and leave it at that.
But, if we go back to apply_form_for_options! we'll see another solution:
as = options[:as]
So you could supply the :as option to form_for to generate a DOM ID for your form by hand:
<%= form_for(@user, :as => 'user_form') do |f| %>
You'd have to make sure that the :as value was unique within the page though.
Executive Summary:
- If your model has an attribute that behaves like a primary key, then define your own
to_key method that returns it.
- Or, supply an appropriate
:as option to form_for.
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