资源下载比较单个字符到字符数组 [英] Java Compare single char to char array

问题描述

我需要比较单个字符到字符数组，看看是否数组有字符。

I need to compare single char to char array and see if array has that char.

我目前的code是这样的：

My current code looks like this:

public boolean isThereChar(char[] chaArray, String chr){
    boolean bool = false;
    for(int i=0; i < chaArray.length; i++)
            {
                if(chr.equals(chaArray[i])){
                    bool = true;
                }
            }
            return bool;
}

编辑备注：

感到迷糊真是不好意思！我只是一个Java初学者= /结果
基本上我写的小游戏的刽子手用GUI。结果
我的程序读取过的文本文件，并随机选择其中玩家猜测的话，那么像这样打印出来的隐藏方式：_ _ _ _ _结果
在这种情况下，我想玩家输入的字符或字符串（人能猜到或者整个单词或只是一个字母）结果
然后我想我的程序采取信函或串并比较隐蔽我的话结果

Really sorry for being confusing! I am just a Java Beginner =/
Basically I am writing small Hangman game with GUI.
My program reads off text file and randomly chooses word which player has to guess, then prints it out in hidden manner like this: _ _ _ _ _
In this case I want player to input character or string (person can guess either whole word or just one letter)
Then I want my program to take that letter or string and compare to my hidden word

继$ C $，C选择单词，隐藏它：

Following code chooses word and hides it:

public String pickWord(){
    String guessWord = (wordsList[new Random().nextInt(wordsList.length)]);
    return guessWord.toLowerCase();
}

//Hides picked word
public char[] setWord(){
    char[] word = new char[pickWord().length() * 2];
    for (int i = 0; i < word.length; i+=2) {
        word[i] = '_';
        word[i + 1] = ' ';
    }
    return word;
}

然后输入的人他的性格，他猜测有以下code编程：

Then person input his character which he guesses to program with following code:

public void actionPerformed(ActionEvent e) {
    String action = e.getActionCommand();

    if (action == "Guess Letter"){
        inputChar = JOptionPane.showInputDialog("Please enter letter (a-z)");
        if (inputChar.length() > 1){
            GuessedLetters glr = new GuessedLetters(inputChar);
            glr.setInString(inputChar);
            //For testing purposes
            System.out.println("This is String: " +glr.getInString());              
        }else{
        GuessedLetters glr = new GuessedLetters(inputChar);
        glr.setInChar(inputChar);
        //For testing purposes
        System.out.println("This is Char: " +glr.getInChar());
        }
    }

最后，我想利用这是输入该字符，并比较我的char型数组这是我隐藏的话：

Lastly I want to take that character which was inputted and compare to my array of chars which is my hidden word:

public boolean isThereChar(char[] array, String str){
    return isThereChar(array, str.charAt(0));
}

public boolean isThereChar(char[] array, char c){
    for(int i=0; i<array.length; i++){
        if (array[i] == c) return true;
    }
    return false;
}

我要检查什么呢我的code返回（true或false），但我一直在这样做失败。
（现在我试图调用方法在我的主类，以检查它，如果你可以给我提示，如何做到这一点，否则请让我知道。）

I want to check what does my code returns (true or false), but I keep failing at doing so. (Right now I am trying to call method in my main class to check it, if you can give me tips how to do it otherwise please let me know.)

推荐答案

让我们来看看，如果我得到你所需要的：

Let's see if I got what you need :

public void actionPerformed(ActionEvent e) {
    String action = e.getActionCommand();
    if (action == "Guess Letter"){
        inputChar = JOptionPane.showInputDialog("Please enter letter (a-z)");
        if (inputChar.length() > 1){ //User input is a string here, right?
            GuessedLetters glr = new GuessedLetters(inputChar);
            glr.setInString(inputChar);
            System.out.println(wordToGuess.contains(glr.getInString())); //This will print true if wordToGuess is equal to glr.getInString() or if it just contains it
            //For testing purposes
            System.out.println("This is String: " +glr.getInString());              
        }else{ //Here the user gave us just a character, so we've got to know if this character is contained in the word, right?
        GuessedLetters glr = new GuessedLetters(inputChar);
        glr.setInChar(inputChar);
        System.out.println(wordToGuess.contains(glr.getInChar()); //This will print true if your char is in the wordToGuess string
        //For testing purposes
        System.out.println("This is Char: " +glr.getInChar());
        }
    }
}

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