如何从 Rails 中的控制器调用 javascript 函数 [英] how to call javascript functions from the controller in rails

问题描述

我正在尝试从 Rails 3.2 应用程序中的控制器调用 javascript 函数(实际上是 coffeescript).

I'm trying to call a javascript function (actually coffeescript) from a controller in a Rails 3.2 app.

我收到一个在此操作中多次调用渲染和/或重定向错误.

我的代码如下所示:

#Model.controller

def index
  @models = Model.all
  my_action if current_user.name == "Bob" #or some other general conditional
  ...and some stuff
  respond_to do |format|
    format.html
    format.js #this is needed to handle ajaxified pagination
  end
end

def my_action
  respond_to do |format|
    format.js { render :js => "my_function();" } #this is the second time format.js has been called in this controller! 
  end
end


#functions.js.coffee.erb

window.my_function = ->
  i = xy
  return something_amazing

从控制器调用js函数的正确方法是什么?

What is the correct way to call a js function from the controller?

推荐答案

伙计，你错过了块的参数.主要错误.

Man, you missed argument for block. Primary mistake.

def my_action
  #respond_to do # This line should be
  respond_to do |format|
    format.js { render :js => "my_function();" }
  end
end

Yoshiji 先生的观点是对的.但是你的错误是在服务器端，还没有到达客户端.

And MrYoshiji's point is right. But your error was on server side, had not reached client side yet.

风格方面，我觉得如果js代码只有一个函数调用就好了.如果js代码比较多，最好渲染js模板

For the style, I think that's okay if the js code is one function call only. If more JS code, it's better to render js template

 # controller
 format.js

 # app/views/my_controller/my_action.js.erb
 my_function();
 // and some more functions.

更新:如何解决双重渲染问题

Update: How to fix double rendering problem

如果条件满足，您必须让 #index 返回，否则该方法将继续执行并导致渲染两次或更多次.像这样修复它:

You must have your #index return if condition met, or the method will continue to execute and cause rendering twice or more. Fix it like this:

def index
  @models = Model.all
  if current_user.name == "Bob"
    return my_action
  else
    # ...and some stuff
    respond_to do |format|
      format.html
      format.js #this is needed to handle ajaxified pagination
  end
end

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