rails 从 url 中删除控制器路径 [英] rails remove controller path from the url

问题描述

我认为有以下循环

<% @posts.each do |post| %>
     <%= link_to post do %>
           Some html
     <% end %>
<% end %>

以上代码将生成链接为 localhost:3000/posts/sdfsdf-sdfsdf

The above code will generate link as localhost:3000/posts/sdfsdf-sdfsdf

但我想将链接设为 localhost:3000/sdfsdf-sdfsdf

这是我的路线

  resources :posts, except: [:show]

  scope '/' do
    match ':id', to: 'posts#show', via: :get
  end

推荐答案

你可以这样做:

#config/routes.rb
resources :posts, path: "" #-> domain.com/this-path-goes-to-posts-show

--

此外，请确保将其放在路线的底部；因为它将覆盖任何先前的路由.例如，domain.com/users 将重定向到 posts 路径，除非 posts 路径定义在 routes 的底部.rb 文件

Also, make sure you put this at the bottom of your routes; as it will override any preceding routes. For example, domain.com/users will redirect to the posts path unless the posts path is defined at the bottom of the routes.rb file

--

friendly_id

为了实现基于 slug 的路由系统(有效)，您将最适合使用 friendly_id.这允许 .find 方法为扩展模型查找 slug 和 id:

In order to achieve a slug-based routing system (which works), you'll be best suited to using friendly_id. This allows the .find method to look up slug as well as id for extended models:

#app/models/post.rb
Class Post < ActiveRecord::Base
   extend FriendlyID
   friendly_id :title, use: [:slugged, :finders]
end

这将允许您在控制器中使用以下内容:

This will allow you to use the following in your controller:

#app/controllers/posts_controller.rb
Class PostsController < ApplicationController
   def show
       @post = Post.find params[:id] #-> this can be either ID or slug
   end
end

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