Rails 4 形式 - 没有将模型隐式转换为字符串 [英] Rails 4 form - no implicit conversion of Model into String

问题描述

添加辅助方法并编辑表单后，出现此错误

帖子中的类型错误#create显示/Users/jim/project/test/app/views/posts/_form.html.erb 其中第 2 行提出:没有将问题隐式转换为字符串提取的源代码(围绕第 2 行):12 <%= show_random(@question)[:title] %>3app/helpers/questions_helper.rb:4:in`show_random'app/views/posts/_form.html.erb:2:在`_app_views_posts__form_html_erb___4147312638633006209_2202637820'app/views/posts/new.html.erb:3:在`_app_views_posts_new_html_erb___3518261482060642021_2203102520'app/controllers/posts_controller.rb:33:in `create'要求参数:{utf8"=>✓"，authenticity_token"=>MK1wiBKc8MqXsKPtvbgJWaBNAaZ7kHm7RDVC8ZYRMNc="，"post"=>{"question_id"=>"1","内容"=>""},提交"=>创建帖子"}

但如果满足Post模型的验证，则不会出现此错误.所以我猜测(不确定)在我的 Posts 控制器 的 create 操作中我的 if else 语句 有问题，但我没有不知道怎么修.

questions_helper.rb

模块 QuestionsHelperdef show_random(随机)JSON.parse(random).with_indifferent_access结尾结尾

_form.html.erb

<%= show_random(@question)[:title] %><%= form_for(@post) 做 |f|％＞<%= render 'shared/error_messages', object: f.object %><div><%= f.hidden_​​field :question_id, :value =>show_random(@question)[:id] %><br>

<div><%= f.label :content%><br><%= f.text_area :content %>

<div><%= f.submit %>

<%结束%>

posts_controller.erb

 def new@post = Post.new@question = cookies[:question] ||= Question.random # random 方法使用 to_json 返回一个随机问题序列化记录结尾定义创建@post = current_user.posts.build(post_params)如果@post.saveflash[:success] = "帖子创建成功！"别的@question = Question.where(id: params[:post][:question_id]).first呈现新"结尾

解决方案

感谢@sissy 的评论，我发现了问题.

我应该通过 @question = cookies[:question] 而不是 @question = Question.where(id: params[:post][:question_id]).first 在我的 posts 控制器

的 create 操作中

感谢大家的帮助.

After adding a helper method and edit my form, I'm getting this error

TypeError in Posts#create

Showing /Users/jim/project/test/app/views/posts/_form.html.erb where line #2 raised:

no implicit conversion of Question into String

Extracted source (around line #2):

1
2      <%= show_random(@question)[:title] %>
3

app/helpers/questions_helper.rb:4:in `show_random'
app/views/posts/_form.html.erb:2:in `_app_views_posts__form_html_erb___4147312638633006209_2202637820'
app/views/posts/new.html.erb:3:in `_app_views_posts_new_html_erb___3518261482060642021_2203102520'
app/controllers/posts_controller.rb:33:in `create'

Request

Parameters:

{"utf8"=>"✓",
 "authenticity_token"=>"MK1wiBKc8MqXsKPtvbgJWaBNAaZ7kHm7RDVC8ZYRMNc=",
 "post"=>{"question_id"=>"1",
 "content"=>""},
 "commit"=>"Create Post"}

But this error won't appear if the validations of Post model are met. So I'm guessing (not sure) there's something wrong with my if else statement in my create action of my Posts controller but I don't know how to fix it.

questions_helper.rb

module QuestionsHelper

    def show_random(random)
        JSON.parse(random).with_indifferent_access
    end

end

_form.html.erb

<%= show_random(@question)[:title] %>

<%= form_for(@post) do |f| %>

  <%= render 'shared/error_messages', object: f.object %>

  <div>
    <%= f.hidden_field :question_id, :value => show_random(@question)[:id] %><br>
  </div> 

  <div>
    <%= f.label :content %><br>
    <%= f.text_area :content %>
  </div>

  <div>
    <%= f.submit %>
  </div>
<% end %>

posts_controller.erb

       def new
         @post = Post.new
         @question = cookies[:question] ||= Question.random  # the random method return a random question serialized record using to_json
       end

       def create
          @post = current_user.posts.build(post_params)
           if @post.save
             flash[:success] = "Post created successfully!"
           else
             @question = Question.where(id: params[:post][:question_id]).first
           render 'new'
        end

解决方案

I have found the problem thanks to @sissy comment.

I should pass @question = cookies[:question] instead of @question = Question.where(id: params[:post][:question_id]).first in my create action of my posts controller

Thanks everyone for your help.

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