结合使用PHP键/值和输出组合阵列两个数组 [英] Combine two arrays on key/value and output combined array with PHP
问题描述
货架我对这个大脑，发现了类似的情况很多例子，不过解决方案似乎并不匹配。
Racking my brain on this, found many examples of similar situations however the solutions don't seem to match up.
我有两个数组被建成为SQL查询在不同数据库的结果。
I have two arrays being built as the result of SQL queries on different databases.
一个人来通过格式化为这样的：
One is coming through formatted as such:
$data = array([$sku] => array(['LocalSKU'] => $sku,
['Price'] => $msrp,
['Price2'] => $wholesale,
['Price3'] => $distributor,
['Price4'] => $map))
另外数组被格式化为这样的：
The other array is formatted as such:
$matchme = array([0] => array(['entity_id'] => $entity_id,
['sku'] => $sku,
['type_id'] => $type_id))
目前，我可以得到单独的数据通过投其所好：
Currently, I can get the individual data to match up via:
echo $matchme[0]['sku'];
echo $matchme[0]['entity_id'];
echo $matchme[0]['type_id'];
echo $data[$matchme[0]['sku']]['Price'];
echo $data[$matchme[0]['sku']]['Price2'];
echo $data[$matchme[0]['sku']]['Price3'];
echo $data[$matchme[0]['sku']]['Price4'];
然而，当我试图在两个数组合并匹配的行，我得到一个空数组。 $ data数组包含74唯一$ SKU和$ matchme是检查那些$ SKU的针对数据库和61元返回一个数组的结果。因此，合并后的数组应该基于$ SKU有61元素再配定价数据。
However, when I try and merge the matching rows in both arrays, I get an empty array. The $data array contains 74 unique $sku, and $matchme is the result of checking those $sku's against a database and returning an array with 61 elements. So, the combined array should have 61 elements with matched pricing data based on the $sku.
我如何在尝试建立组合阵列的下方，任何人都可以点我对我在做什么错了？
How I am attempting to build the combined array is below, can anyone point me towards what I am doing wrong?
foreach($matchme as $key){
if(in_array($matchme[$key]['sku'], $data)){
$matched_luggage[$matchme[$key]['sku']][] = array(
'sku' => $matchme[$key]['sku'],
'entity_id' => $matchme[$key]['entity_id'],
'type_id' => $matchme[$key]['type_id'],
'MSRP' => $data[$matchme[$key]['sku']]['Price'],
'Wholesale' => $data[$matchme[$key]['sku']]['Price2'],
'Distributor' => $data[$matchme[$key]['sku']]['Price3'],
'MAP' => $data[$matchme[$key]['sku']]['Price4']
);
}
}
在上面的例子中，评估$键0，['SKU']是匹配的。
In the above example, evaluate $key as 0, and the value of ['sku'] are matching.
------------------------编辑---------------------- ---
------------------------Edited-------------------------
根据要求这里是截断空间的print_r（$数据）的结果是：
Per request, here is the result of print_r($data) truncated for space:
Array
(
[12PK-TITANIUM-CR123A] => Array
(
[LocalSKU] => 12PK-TITANIUM-CR123A
[Price] => 11.76
[Price2] => 10.32
[Price3] => 0
[Price4] => 0
)
[AA-CLAMSHELL] => Array
(
[LocalSKU] => AA-CLAMSHELL
[Price] => 0.25
[Price2] => 0
[Price3] => 0
[Price4] => 0
)
[AAA-CLAMSHELL] => Array
(
[LocalSKU] => AAA-CLAMSHELL
[Price] => 0.25
[Price2] => 0
[Price3] => 0
[Price4] => 0
)
[AE-AEL280PI] => Array
(
[LocalSKU] => AE-AEL280PI
[Price] => 0
[Price2] => 0
[Price3] => 0
[Price4] => 0
) )
根据要求在这里的print_r（$ matchme）的结果截断空间：
Per request, here is the result of print_r($matchme) truncated for space:
Array
(
[0] => Array
(
[entity_id] => 693
[sku] => 12PK-TITANIUM-CR123A
[type_id] => simple
)
[1] => Array
(
[entity_id] => 2596
[sku] => AE-AEL480HL
[type_id] => simple
)
[2] => Array
(
[entity_id] => 2597
[sku] => AE-AEL600-T6
[type_id] => simple
)
[3] => Array
(
[entity_id] => 2598
[sku] => AE-AEWL2
[type_id] => simple
) )
根据要求这里是$ matched_luggage的期望的结果：
Per request, here is the desired result of $matched_luggage:
$matched_luggage = array( [12PK-TITANIUM-CR123A] => array([sku] => 12PK-TITANIUM-CR123A,
[entity_id] => 693,
[type_id] => simple,
[Price] => 11.76,
[Price2] => 10.32,
[Price3] => 0,
[Price4] => 0))
每个SKU匹配一个额外的数组。
with an additional array per matched sku.
推荐答案
试试这个：
foreach ($matchme as $arrProduct) {
if (isset($data[$arrProduct['sku']])) {
$arrMerged[$arrProduct['sku']]=array_merge($arrProduct, $data[$arrProduct['sku']]);
}
}
print_r($arrMerged);
您code不工作的原因是在这里：
The reason your code doesn't work is here:
if(in_array($matchme[$key]['sku'], $data)) [...]
什么 in_array（）所做的就是告诉你无论你的针的（你的情况SKU字符串）形式存在数组值的草垛的（在你的情况，$数据）。你基本上是试图将字符串匹配到一个数组，而不是另一个字符串。
What in_array() does is tell you whether your needle (in your case the SKU string) exists as a value of array haystack (in your case, $data). You are essentially trying to match a string to an array, rather than another string.
你真正想要的仅仅是相匹配的SKU字符串的$数据的关键，为此，使用isset（）可能是最简单的方法。
What you really want is just to match the SKU string to the key of $data, for which isset() is probably the simplest approach.
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