排序(名称)使用合并排序 [英] Sorting (names) using Merge Sort

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本文介绍了排序(名称)使用合并排序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

排序重复字符串有问题,

having problem sorting repeated Strings,

这是我的code ..

and here's my code..

我成功排序的第一个数组但在第二(反复字符串),似乎不是在有序输出,你可以帮我追查什么是错在我的code ..

i successfully sorted the first array but in the second (with repeated strings) it seems not in orderly output, can you help me to trace whats wrong in my code..

import java.util.*;

public class NewClass {
    public static void main(String[] args) {
        String[] ClassOne = { "Kring", "Panda", "Soliel", "Darryl", "Chan", "Matang", "Jollibee.", "Inasal" };
        String[] ClassTwo = { "Minnie", "Kitty", "Madonna", "Miley", "Zoom-zoom", "Cristine", "Bubbles", "Ara", "Rose", "Maria" };
        String[] names = new String[ClassOne.length + ClassTwo.length];

        mergeSort(ClassOne);
        mergeSort(ClassTwo);

        merge(names, ClassOne, ClassTwo);

        mergeSort(names);
        //Arrays.sort(names);

        for (String ClassThree : names) {
            System.out.println(ClassThree);
        }
    }

    public static void mergeSort(String[] names) {
        if (names.length > 2) {
            String[] left = new String[names.length / 2];
            String[] right = new String[names.length - names.length / 2];

            for (int i = 0; i < left.length; i++) {
                left[i] = names[i];
            }

            for (int i = 0; i < right.length; i++) {
                right[i] = names[i + names.length / 2];
            }

            mergeSort(left);
            mergeSort(right);
            merge(names, left, right);
        }
    }

    public static void merge(String[] names, String[] left, String[] right) {
        int a = 0;
        int b = 0;
        for (int i = 0; i < names.length; i++) {
            if (b >= right.length || (a < left.length && left[a].compareToIgnoreCase(right[b]) < 0)) {
                names[i] = left[a];
                a++;
            } else {
                names[i] = right[b];
                b++;
            }
        }
    }
}

和继承人的输出:

Ara
Chan
Cristine
Bubbles
Jollibee.
Inasal
Kring
Madonna
Matang
Miley
Minnie
Kitty
Panda
Rose
Maria
Soliel
Darryl
Zoom-zoom

...

推荐答案

修改

if (names.length > 2) {

if (names.length >= 2) {

输出

Ara
Bubbles
Chan
Cristine
Darryl
Inasal
Jollibee.
Kitty
Kring
Madonna
Maria
Matang
Miley
Minnie
Panda
Rose
Soliel
Zoom-zoom

这篇关于排序(名称)使用合并排序的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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