计算一个文本文件中的唯一单词量？ （不允许使用哈希） [英] count amount of unique words in a text file? (Not allowed to use Hash)

问题描述

我怎么能指望在一个文本文件中重复的单词，使用数组？

我的程序能够在文件中打印出总的话，但我怎么能得到我的程序打印不同的单词数量，还打印出这样的重复的单词数的列表：

蛋糕：4
一：320
海贼王：2
24

（大写字母和小写字母词被认为是同一个词）

 无效的FileReader（）{
    的System.out.println（Oppgave A）;
    INT totalWords = 0;
    INT uniqueWords = 0;
    的String []字=新的String [35000]
    的String [] = wordC新的String [3500];
    尝试{
        文件FR =新的文件（Alice.txt）;
        扫描仪SC =新的扫描仪（FR）;        而（sc.hasNext（））{
        串词= sc.next（）;
        的String [] =空间words.split（）;
        的String []，逗号words.split（）;
            totalWords ++;
            }
        的System.out.println（Antall ORD SOM ER ER唯恐：+ totalWords）;
    }赶上（例外五）{        的System.out.println（找不到文件）;    }
 

解决方案

每当你添加你需要检查的话阵列中已经存在的话。
为了比较，你将需要使用：

  word1.equalsIgnoreCase（字词）;
 

How can I count repeated words in a text file, using an array?

My program is able to print out total words in the file, But how can I get my program to print the number of different words and also have printed out a list of the number of the repeated words like this:

Cake: 4 a: 320 Piece: 2 of 24

   (Words with capital letters and small letters are considered the same word)

void FileReader() { 


    System.out.println("Oppgave A");
    int totalWords = 0; 
    int uniqueWords = 0; 
    String [] word = new String[35000];
    String [] wordC = new String [3500];
    try {
        File fr = new File("Alice.txt");
        Scanner sc = new Scanner (fr);

        while(sc.hasNext()){
        String words = sc.next();
        String[] space = words.split(" ");
        String[] comma = words.split(",");
            totalWords++;


            }
        System.out.println("Antall ord som er lest er: " + totalWords);         
    } catch (Exception e) {

        System.out.println("File not found");

    }

解决方案

Every time you are adding a word you need to check if the word already exists in your array. To compare you will need to use:

 word1.equalsIgnoreCase(word2);

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