你可以追加到基于if语句条件数组中的特定元素？ [英] Can you append to specific elements in an array based on if statement conditions?

问题描述

我是一个开发者训练营的学生，在和我的一个项目的问题。我们以Ruby code一个隐语页面。我把它通过测试，直到它需要接受多个字的一点：

 高清pig_latina（字）
  ＃万能变量
元音= ['一'，'E'，'我'，'O'，'U']
user_output =
  ＃如果词以元音开头加上'的方式'
  如果vowels.include？（字[0]）
     user_output =字+'的方式'
  ＃元音到年底之前在移动一个单词的开头第一个辅音
  其他
    word.split（）each_with_index做|。信中，指数|      如果vowels.include？（字母）
        user_output =字[指数..- 1] +字[0..index-1] +'唉'
      打破
      结束
    结束
  结束
  ＃需要以'曲'开头的单词，并将其移动到公共汽车后面，并增加了AY
  如果字[0,2] =='曲'
  user_output =字[2 ..- 1] +'码头'
  结束
  ＃需要包含曲字，并将其移动到公共汽车后面，并增加了AY
  如果字[1,2] =='曲'
  user_output =字[3 ..- 1] +字[0] +'码头'
  结束
  ＃打印结果
  user_output
结束
 

我不知道该怎么做。这不是功课或任何东西。我试过

 字= phrase.split（）
    words.each做|字|
    如果vowels.include？（字[0]）
      字+'的方式'
 

但我认为其他语句是搞乱了这一切。任何有识之士将大大AP preciated！谢谢！

解决方案

 高清pig_latina（字）
  preFIX =字[0％（重）（A E I O U）.MAP {|元音| ＃{}一词AEIOU的.index（元音）}。分]
  preFIX ='曲'如果字[0,2] =='曲'
  prefix.length == 0？ ＃{}字路：＃{字[prefix.length ..- 1]}＃{preFIX} AY
结束短语=狗跳过了鹌鹑
翻译= phrase.scan（/ \\ W + /）{地图|。字| pig_latina（字）}。加入（）.capitalize把翻译＃=＆GT; Ethay ogd​​ay umpedjay overway ethay ailquay
 

I am a developer bootcamp student and was having an issue with one of my projects. We are using Ruby to code a Pig Latin page. I got it passing tests up until the point where it needs to accept multiple words:

def pig_latina(word)
  # univeral variables
vowels = ['a','e','i','o','u']
user_output = ""
  # adds 'way' if the word starts with a vowel
  if vowels.include?(word[0]) 
     user_output = word + 'way'     
  # moves the first consonants at the beginning of a word before a vowel to the end  
  else 
    word.split("").each_with_index do |letter, index|

      if vowels.include?(letter)
        user_output = word[index..-1] + word[0..index-1] + 'ay'
      break
      end
    end 
  end   
  # takes words that start with 'qu' and moves it to the back of the bus and adds 'ay'
  if word[0,2] == 'qu'
  user_output = word[2..-1] + 'quay'
  end
  # takes words that contain 'qu' and moves it to the back of the bus and adds 'ay'
  if word[1,2] == 'qu'
  user_output = word[3..-1] + word[0] + 'quay'
  end
  # prints result
  user_output
end

I don't know how to do it. This isn't homework or anything. I tried

  words = phrase.split(" ")
    words.each do |word|
    if vowels.include?(word[0])
      word + 'way'

but I think that the else statement is messing it all up. Any insight would be greatly appreciated! Thanks!!

解决方案

def pig_latina(word)
  prefix = word[0, %w(a e i o u).map{|vowel| "#{word}aeiou".index(vowel)}.min]
  prefix = 'qu' if word[0, 2] == 'qu'
  prefix.length == 0 ? "#{word}way" : "#{word[prefix.length..-1]}#{prefix}ay"
end

phrase = "The dog jumped over the quail"
translated = phrase.scan(/\w+/).map{|word| pig_latina(word)}.join(" ").capitalize

puts translated  # => "Ethay ogday umpedjay overway ethay ailquay"

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