PHP数组数组中的删除重复的连续occurances [英] php array removing successive duplicate occurances in an array

问题描述

我想问一下这里的问题是：

反正是有，我可以从下而只保留第一个数组中删除连续重复？

阵列如下：

<$p$p><$c$c>$a=array(\"1\"=>\"go\",\"2\"=>\"stop\",\"3\"=>\"stop\",\"4\"=>\"stop\",\"5\"=>\"stop\",\"6\"=>\"go\",\"7\"=>\"go\",\"8\"=>\"stop\");

我要的是有包含数组：

  $ a =阵列（1=＆gt;中去，2=＆gt;中停，3=＆gt;中去，7 = GT;停止）;
 

任何建议会有所帮助。问候。

解决方案

您只需做一些这样的：

 如果（电流（$ A）！== $ new_val）
    $ A [] = $ new_val;
 

假设你没有操纵之间，你可以使用数组电流（）这比每次计算它在计数（$ A）-1

The question i would like to ask here is:

Is there anyway that i can remove the successive duplicates from the array below while only keeping the first one?

The array is shown below:

$a=array("1"=>"go","2"=>"stop","3"=>"stop","4"=>"stop","5"=>"stop","6"=>"go","7"=>"go","8"=>"stop");

What I want is to have an array that contains:

$a=array("1"=>"go","2"=>"stop","3"=>"go","7"=>"stop");

Any suggestions would help. Regards.

解决方案

You can just do something like:

if(current($a) !== $new_val)
    $a[] = $new_val;

Assuming you're not manipulating that array in between you can use current() it's more efficient than counting it each time to check the value at count($a)-1

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